cannot make more than one client connection over a NAT device

network A : 192.168.1.x/24
because network A node come over full, so i build a NAT to free more IP to use
network B : 192.168.2.x/24
i try to build a NAT by linksys router and netscreen firewall, everything work fine, but fail to copy file from network B to network A (which is win 2003 server share folder), it can copy file sometime and drop it out, even smail file size.

I found the knowledge base on microsft, it's the exactly case.
http://support.microsoft.com/default.aspx?scid=KB;en-us;301673

however, it seem no solution on it, what i should solve it, build a linux samba to share or build a ftp service to share a folder on win2003, but seem so strange that to let internal user copy file between same office location.

pls advise or any other solution to free up the ip usage (my office grow up to 250 pc), thanks.
edmondto2Asked:
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grsteedCommented:
Why not just change the mask to a /23 (255.255.254.0) This would give you an IP range of 192.168.0.1 to 192.168.1.254 or 510 IP's all on the same network. This is known as supernetting or combining multiple class C addresses into one network.

If you don't want to use the zero subnet you could use 192.168.2.1 through 192.168.3.254 with a /23 mask and get the same number of IP's.

Cheers,

Gary
edmondto2Author Commented:
because i concern that there will be too much collusion on the network and slow down the whole network,
actually, would it happen?
and the win 2003 server dhcp can config the allocate ip range from 192.168.1.1 to 192.168.2.254?

thanks
grsteedCommented:
Is it a switched network? If so than collisions wouldn't be a problem.  It would be a larger broadcast domain and depending on how much broadcast traffic there is it might pose a problem, but if it's not a problem now, then adding 10-20 more machines probably wouldn't be noticable.

You can change the DHCP scope to use the /23 mask but the addresses would need to be 192.168.0.x - 192.168.1.x or 192.168.2.x - 192.168.3.x.  The only way you could get both the .1 and .2 ranges on the same network would be to use a /22 mask which would give you .0 thru .3 and ~ 1020 hosts.

Cheers,

Gary

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