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Error: null values displaying

Posted on 2006-04-23
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Last Modified: 2010-03-31
This program will take any xml file and show recursivly the depth of each tag
Problem is that the values are showing up as null when displayed

import org.w3c.dom.*;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.FactoryConfigurationError;
import javax.xml.parsers.ParserConfigurationException;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
import java.io.IOException;
import java.io.File;

public class XMLDisplay {
   //Global variables
  private static int depth = 0;
  private static Document document;
  private static DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
 
   //Main method, calls recursive function
  public static void main(String[] args) {
    try {
      DocumentBuilder builder = factory.newDocumentBuilder();
      document = builder.parse(new File(args[0]));
      listAll(document, depth);  
    } catch (SAXParseException spe) {
      // Error generated by the parser
      System.out.println("\n** Parsing error" + ", line " +
                         spe.getLineNumber() + ", uri " + spe.getSystemId());
      System.out.println("   " + spe.getMessage());
     
      // Use the contained exception, if any
      Exception x = spe;
     
      if (spe.getException() != null) {
        x = spe.getException();
      }
     
      x.printStackTrace();
    } catch (SAXException sxe) {
      // Error generated during parsing)
      Exception x = sxe;
     
      if (sxe.getException() != null) {
        x = sxe.getException();
      }
     
      x.printStackTrace();
    } catch (ParserConfigurationException pce) {
      // Parser with specified options can't be built
      pce.printStackTrace();
    } catch (IOException ioe) {
      // I/O error
      ioe.printStackTrace();
    }
  }

public static void listAll(Node n, int depth)
  {
    printName(n, depth);   // indent using level
    NodeList children = n.getChildNodes();
    for (int i=0; i < children.getLength(); i++) {
      Node child = children.item(i);
      listAll(child, depth+1);
    }
  }
 
  public static void printName(Node n, int depth) {
    for (int i = 0; i < depth; i ++)
      System.out.print("  ");
    System.out.println(n.getLocalName());
  }
}
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Question by:no158
  • 3
4 Comments
 
LVL 86

Expert Comment

by:CEHJ
ID: 16520470
listAll doesn't call println
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LVL 86

Accepted Solution

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CEHJ earned 2000 total points
ID: 16520481
Sorry - ignore that. You need to check the node and do

System.out.println(n.getNodeName());
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Author Comment

by:no158
ID: 16520917
thanks again
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 16523151
:-)
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