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Tow digit number can be max 99 so the 3 digit number is greated than or equal to 901

so X = 9 Confirm;

if YZ > A B then X Y Z - A B should result X _ _ but it is resulting B _ _ means

YZ < AB and in this case B can be nothing but 8 only

so till now

X = 9; B=8; C = 1;

XYZ can be max 999 and min 901

AB can be min 10 and max 99 so addition wil not cross

9 Y Z

+ A 8

=====

1 D E F

9 Y Z

- A 8

=====

8 G A

NOw D can be only 0 or 1 as 5 digit number will be between 1001 to 1198

Since c is already 1 so D = 0;

Till now

X = 9; B=8; C = 1; D = 0;

Remaining Y Z A E F G are among 2,3,4,5,6,7,

Take the addition case

if z=2 then F should be 0 so which is not possible so Z is not 2

if z = 3 then F will be 1 again not possible

if z = 4 then F will be 2 possible

sub case then A will be 6

remaining Y E F among 3,5,7

Check othenr if fails increasy Z and try again

and so on you will reach

D=0 ; C=1 ; E=2; F=3 ;Y=4 ; Z=5 ;G=6 ; A=7 ; B=8 ; X=9 ;