asked on

read files from a directory ...

Hello experts,

I have several files such as:

dog.pet, cat.pet, bird.pet, elephant.pet ...etc., all in the "Animal" folder.
There are also files called ant.bad, fly.bad ... etc. in the Animal folder as well.

How do I open the *.pet files, read some info in the file, and then store the filename (eg. dog, cat ...) in to an array ?
I mean I want an array storing : dog, cat, bird, elephant ... etc.
And of course, I don't know how many files in Animal are "*.pet" files at very beginning ...

Is this something possible ? thanks.

CEHJ

Just list the directory

File[] petsFiles = new File("Animal").listFiles();
String[] petNames = new String[petsFiles.length];
// Now copy just the name into petNames

meow00

ASKER

but there are ant.bad & fly.bad in the Animal folder as well ...
And I don't want *.bad files ...

Also, what is the files are in the current folder, how do I call the .listFiles() function ??? thanks.

CEHJ

You can use a FileFilter

File[] petsFiles = new File("Animal").listFiles(new FileFilter() {
public boolean accept(File f) {
return f.getName().toLowerCase().endsWith(".pet");
}
});

meow00

ASKER

I see, thanks...

What do I do if the files are in the current folder (same folder as the main program)

File[] petsFiles = new File("").listFiles(); or
File[] petsFiles = new File().listFiles();
doesn't seem to work ...:-(

CEHJ

File[] petsFiles = new File(".").listFiles(new FileFilter() {

meow00

ASKER

thanks so much ... one last question ... how do I copy the name before .pet to the new array ? thanks.

ASKER CERTIFIED SOLUTION

CEHJ

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CEHJ

:-)