Posted on 2006-04-29
A moonshiner produces pure ethanol (ethyl alcohol) and stores it in a stainless steel tank in the form of a cylinder 0.300m in diameter with a tight-fitting piston at the top. The total volume of the tank is (250L or 0.250m^3). In an attempt to squeeze a little more into the tank, the moonshiner piles 1420kg of lead bricks on top of the piston. What additional volume of ethanol can the moonshiner squeeze into the tank? (Assume that the wall of the tank is perfectly rigid.)
Well the compressability of ethyl alcohol is (1.10 * 10^-13)
And I know that k (compressibility)...
k = - 1/v_0 * (v - v_0)/(p - p_0)
My target variable is v (finial volume), but how do I figure out p & p_0? Or what other equations can I use to figure out all the unknowns? Am I even taking the right approach?