dcrudo
asked on
$_POST $_GET Question in PHP ...
Dear All,
I have the following:
if($_GET['cmd'] == "")
{
if($_POST['cmd'] == $nil)
{
$cmd = "";
}
else
{
$cmd = $_POST['cmd'];
}
}
else
{
$cmd = $_GET['cmd'];
}
Basically I would like to be able to pass variables either with post (from a form) or with get (from a string in the url) to a PHP script.
The problem is that using the condition above, if for instante the $_POST variable is empty ...the scripts gives an error like:
"Undefined index: cmd in /var/www/vhosts/demo.shiro
Is there a way to tell PHP that if the variable is not there...just ignore it?
Thank you!
Dave.
I have the following:
if($_GET['cmd'] == "")
{
if($_POST['cmd'] == $nil)
{
$cmd = "";
}
else
{
$cmd = $_POST['cmd'];
}
}
else
{
$cmd = $_GET['cmd'];
}
Basically I would like to be able to pass variables either with post (from a form) or with get (from a string in the url) to a PHP script.
The problem is that using the condition above, if for instante the $_POST variable is empty ...the scripts gives an error like:
"Undefined index: cmd in /var/www/vhosts/demo.shiro
Is there a way to tell PHP that if the variable is not there...just ignore it?
Thank you!
Dave.
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ASKER
Hi,
I will split the points because more than one solution was good! Actually I've used parts of all of them ;
Thx again!
Dave
I will split the points because more than one solution was good! Actually I've used parts of all of them ;
Thx again!
Dave
You can also just use the $_REQUEST array instead of the complicated if structure:
$cmd = $_REQUEST['cmd'];
-r-