I need a simple formula to calculate the efficiency of an electrolysis device
Posted on 2006-05-06
I need a simple formula to verify my math concerning the efficiency of an electrolysis device. (Actual percentage of electrons used to crack water)
These are the numbers I have to work with: Total amount of electrons sent to the electrolizer from the input power supply is 100 coulombs.(1000 joules if this helps). …Also refer to statement below….
(1 mole of water produces 1 mole of H2 and 0.5 mole of O2 so that would be 24359cc/mole * 1.5mole / 18cc/mole = 2030cc of H2+O2 per cc of water at 75 °F the vapor pressure of water is about .03 atmospheres….)
Using the above information what would be the volume of total gas if the device were “100% efficient”. Once I am sure of this amount, it will be easy to calculate future experiments
From actual test, the total gas produced (H and O) is 3.5cc for test 1 and 5.75 cc for test 2.
Keep in mind guys (and gals) I’m not an engineer or chemist, just a humble inventor trying to figure this out. So please have mercy on me!!!!!