preg_match preg_replace in javascript.

What about: preg_match preg_replace?

var x = "This is a sentence";
x.replace("is","was");

if(x.indexOf("sentence") != -1)
{
alert("We found a match");
}

BTW, an alternative for "preg_match" would be

/RegExp/.exec ("string");

This does the same thing as "string".match ( /RegExp/ );

var x = "some_long_string";
x = x.split('_', 1);

But $x = str_split($x, 1);

Means to put each char into an array.

v.match (/^\s|\s$/)
doesn't work.

result_array = v.match ( /^\s|\s$/ );

see also http://developer.mozilla.org/en/docs/Core_JavaScript_1.5_Reference:Global_Objects:String:match .

I wanted to use it in an if?

eg.

    if(v.match ('/^\s|\s$/'))
    {
//
}

well without the '

And for this: /[^A-Za-z0-9\'"|_\[\]\- ]/ where I am escaping the ' do I need to do that?

Ok I am all good except:

var x = "some_long_string";
x = x.split('_', 1);

But $x = str_split($x, 1);

Means to put each char into an array.

1)

    if( /^\s|\s$/.test(v)  ) {
 ...
    }


There should be no 'quotes' around the slashes (/ ... /). In JS regular expressions are native objects so you don't need to quote them around '...'.

2)

You do not need to escape the ', because it isn't special in RegExp.

/[^A-Za-z0-9'"|_\[\]\- ]/

3)

Use
x = x.split ( /\B|\b/ );

array_unique has no equivalent you could use sort and the remove second appearanve of a data
i/e/

a = new Array("X" ,"y" ,"d", "Z", "v","m","r");
a = a.sort();
then use for(...) to compare....

How do I compare it?

function array_unique(arr) {
    var newArray = [];
    var existingItems = {};
    var prefix = String(Math.random() * 9e9);
    for (var ii = 0; ii < arr.length; ++ii) {
        if (!existingItems[prefix + arr[ii]]) {
            newArray.push(arr[ii]);
            existingItems[prefix + arr[ii]] = true;
        }
    }
    return newArray;
}