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how to start a custom application at the default port

Hi

I would like to start my application's default page as the default page for the tomcat instance. When i do http://localhost:8080, i would like to see my application's default page is myapp.html come up. I tried the following setting as suggested in an earlier thread. But it did n't seem to work.
      <Context path=""
            docBase="myapp"
            debug="1" reloadable="true" /> and changed the web.xml under webapps/myapp/WEB-INF to the following.
<welcome-file-list>
<welcome-file>myapp.html</welcome-file>
</welcome-file-list>

Could someone please help.

thx in advance

callrs

Edit your httpd.conf file (which is in the conf folder in your Apache Install). Add to the entries in the DirectoryIndex:
#
# DirectoryIndex: sets the file that Apache will serve if a directory
# is requested.
#
# The index.html.var file (a type-map) is used to deliver content-
# negotiated documents. The MultiViews Option can be used for the
# same purpose, but it is much slower.
#
DirectoryIndex index.html index.html.var

---------
See: http://www.modwest.com/help/kb1-147.html How can I show a default page other than index.html?

schillara_2000

ASKER

friends

I was able to figure it out. thanks. I needed to create that file in the root directory of the app as it was really a dummy file in the servlet processing.

thanks all

ASKER CERTIFIED SOLUTION

GranMod

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