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Numeric + 1 character to textbox in vb6

Here is the problem.
I need to be able to stop users from entering non numeric data to a textbox but still allow them to enter the decimal sign.
I have tried various routines, but nothing seems to be working.
The user would enter 6.00 as in six dollars so they need the decimal point. I do have a module that strips out unwanted characters, but it does not prevent the user from initially entering the characters. Copy and paste is not an issue.
Any ideas or code would be appreciated on this.
0
mindserve
Asked:
mindserve
1 Solution
 
BrownheadCommented:
Here ya go :D

'//Code\\
'This code requires a textbox named Text1
Private Sub Text1_KeyPress(KeyAscii As Integer)
If (Chr(KeyAscii) <> "." And KeyAscii <> vbKeyBack And Not IsNumeric(Chr(KeyAscii))) Then KeyAscii = 0
End Sub
'\\Code//
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JackOfPHCommented:
Private Sub Text1_KeyPress(KeyAscii As Integer)
Select Case KeyAscii
    Case 8, 48 To 57, 46        'valid
    Case Else
        MsgBox ("Invalid")
End Select
end sub
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cquinnCommented:
Passa list of acceptable keys to the function below, and the ascii code of the key being pressed - it will return the ascii code if the key is in the list, or 0 if not
Call it from the On_keypress event of a text box eg the following example will restrict key entry to valid numerics plus decimal point

Private Sub txtNumber_KeyPress(KeyAscii As Integer)
KeyAscii=ValidateEntry(".1234567890",KeyAscii)
End Sub




Public Function ValidateEntry(ValidKeys As String, KeyAscii As Integer) As Integer

On Error GoTo HandleErr

If InStr(ValidKeys, Chr$(KeyAscii)) > 0 Or KeyAscii = 8 Then  'KeyAscii=8 allows the backspace
    ValidateEntry = KeyAscii
Else
    ValidateEntry = 0
End If

ExitHere:
  Exit Function

HandleErr:
  Select Case Err.Number
    Case Else
       MsgBox "Error " & Err.Number & ": " & Err.Description, vbCritical, "modFunctions.ValidateEntry"
  End Select
  Resume ExitHere
' End Error handling block.
End Function
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mindserveAuthor Commented:
:D Thanks Brownhead!
0
 
EDDYKTCommented:
can your routine validate 6.0.0

Just checking
0
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