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IP addressing
Can someone explain the justification for the following answer
IP address : 150.18.0.0.
Subnet mask : 255.255.0.0
Number of hosts = 2^n - 2 = 2^16-2 = 65534. I got this part.
Number of network = 16384. I am not quit sure how did they got this part!
IP address : 150.18.0.0.
Subnet mask : 255.255.0.0
Number of hosts = 2^n - 2 = 2^16-2 = 65534. I got this part.
Number of network = 16384. I am not quit sure how did they got this part!
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yes , its a class B network and 2 unused IP's are set aide for broadcast. Whats wrong with it
Read the Theory good good before making questions.
Makana
CCNA-4
Read the Theory good good before making questions.
Makana
CCNA-4
I don't see where you (or they) are getting 14 bits for the network. 255.255.0.0 = 16 network bits.
thats
11111111+11111111+00000000 +00000000
=16
So? where the problem is for you?
11111111+11111111+00000000
=16
So? where the problem is for you?
ASKER
Thanks I got it now.
ASKER
The first two bit is reserved in class B. So there is only 14 bits. That is what i was asking.
Correction: 2 IPs are set aside, one for Network ID and another for Broadcast Address.
In a classful world, the first 2 bits could be used to determine the class,
01 = A
10 = B
11 = C
These days it's pretty much classless everywhere (in more ways than one) so it doesn't really matter.
Cheers,
Gary
01 = A
10 = B
11 = C
These days it's pretty much classless everywhere (in more ways than one) so it doesn't really matter.
Cheers,
Gary
>Number of hosts = 2^n - 2 = 2^16-2 = 65534. I got this part.
>Number of network = 16384. I am not quit sure how did they got this part!
Looks like your networks are approx 25% of your hosts - to me this would possibly mean that it is assumed that the smallest network consists of four address (network, broadcast, and two host addresses). So, divide your hosts by four and you get the number of maximum possible "networks".
Cheers,
-Jon
>Number of network = 16384. I am not quit sure how did they got this part!
Looks like your networks are approx 25% of your hosts - to me this would possibly mean that it is assumed that the smallest network consists of four address (network, broadcast, and two host addresses). So, divide your hosts by four and you get the number of maximum possible "networks".
Cheers,
-Jon
http://jodies.de/ipcalc tells all you want to know about your IP address...
ASKER
Thanks nirma242. It is pretty good website.
ASKER