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Posted on 2006-05-27
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Can someone explain the justification for the following answer

Number of hosts = 2^n - 2 = 2^16-2 = 65534. I got this part.

Number of network = 16384. I am not quit sure how did they got this part!
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Question by:ittechlab
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MichaelPro earned 80 total points
ID: 16775673
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Author Comment

ID: 16775767
How do they using 14 bits for the network instead of first 16bits.  My understanding is class B hold 255.255.0.0 which is first 16 bit for the network.
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Expert Comment

ID: 16775887
yes , its a class B network and 2 unused IP's are set aide for broadcast. Whats wrong with it
Read the Theory good good before making questions.

Makana
CCNA-4
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Expert Comment

ID: 16775931
I don't see where you (or they) are getting 14 bits for the network. 255.255.0.0 = 16 network bits.
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Expert Comment

ID: 16775951
thats
11111111+11111111+00000000+00000000
=16
So? where the problem is for you?
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Author Comment

ID: 16775991
Thanks I got it now.
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Author Comment

ID: 16775997
The first two  bit is reserved in class B. So there is only 14 bits. That is what i was asking.
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Expert Comment

ID: 16776092
Correction: 2 IPs are set aside, one for Network ID and another for Broadcast Address.
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LVL 11

Expert Comment

ID: 16776152
In a classful world, the first 2 bits could be used to determine the class,

01 = A
10 = B
11 = C

These days it's pretty much classless everywhere (in more ways than one)  so it doesn't really matter.

Cheers,

Gary
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Expert Comment

ID: 16776917
>Number of hosts = 2^n - 2 = 2^16-2 = 65534. I got this part.

>Number of network = 16384. I am not quit sure how did they got this part!

Looks like your networks are approx 25% of your hosts - to me this would possibly mean that it is assumed that the smallest network consists of four address (network, broadcast, and two host addresses).  So, divide your hosts by four and you get the number of maximum possible "networks".

Cheers,
-Jon
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Expert Comment

ID: 16783990
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Author Comment

ID: 16784070
Thanks nirma242. It is pretty good website.
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