How to use GREP to get the results I want?

Posted on 2006-05-31
Medium Priority
Last Modified: 2013-12-16

I have to search for an expression in several log's, but the way I can use grep, the resulting file too large (few 10's of thousands of rows). Therefor there should be an exclude expression to shorten the result.

What I've done:

grep searchterm /path/* > 01

and I do get a file of 40MB.

In file 01 are terms/expression I want to exclude in the result.

How do I use grep to get all rows with "searchterm", but without "" and ""?


Question by:su-n
LVL 43

Assisted Solution

ravenpl earned 1000 total points
ID: 16800223
grep searchterm /path/* | grep -v '' | grep -v '' > 01

Accepted Solution

bryanlloydharris earned 1000 total points
ID: 16802227
Ravenpl is correct, but here is another way:

grep searchterm /path/* | grep -v -e '' -e '' > 01

Also, you might want to try something like this:

grep searchterm /path/* 2>/dev/null | grep -v -e '' -e '' > 01

By putting 2>/dev/null, you are not regarding any error messages.  This is good to do if you get some messages which say:

/some/path: is a directory

Author Comment

ID: 16805752
Thanks alot for your help!

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