matchstick puzzle

Move one of the I to an angle over the =, to form the equivalent to X >= I

Here's the best I can do to draw what I mean in ASCII:

\/  \  |
/\ =  |

transform X into //, and declare the left hand side to be written in italic font.

The task was to make the equation, not the inequality true.
Every match puzzle can be solved by changing the = sign to > or <. This way it's not a challenge.

Take one I from II and lay it over the = to form "X not equal I".  But does that have the same problem as snoyes_jw's solution?  Are you saying that the solution must be an equality?

Matchstick puzzles have sense only if the equal sign remains equal sign. It may be moved, for example V=III-II can be solved as V-III=II, but can't be changed to other relational operator.

Good answer.

The guy who gave me the puzzle said he knew another solution. As he is a mathematician I'm sure that he thought of something more tricky than interpreting // as II in italics. I'm curiously waiting for the alternative solution.

Move 1 match from the X to the other side and treat 2 of the matches on the right as absolute value
/ = | 1 |

Make it as

X=L
or
X=T

where X & L or T become variable.

so, when we replace X with 4 and L with 4;

X=L
4=4   it's true..

another one...

X-= I

of which in programming means X = X - 1

haha..

Take one from the right side, bust it into four smaller pieces and form a 0 and put it above and to the right of the X

X^0 = 1

:)

Only moving one match!

Hi,


X = II  

from II take one and make X so it will be X=X it's true

(No  perfact X )

or
X=II  take one from X and make II you have II = II  it's true

Thanks

Of course, as it stands:

X = II is also true in base 9 :)

Thanks, pallosp.