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an array designed and implemented by user input

Posted on 2006-06-11
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Last Modified: 2010-03-31
Write a program that allows the user to input an array's size, and then prompts the user for all the values to put in the array, and finally prints them all. Make sure that you use exception handling to get user input. You may use either the primitive data type or String arrays.

I have come up with the following source code but the program does not compile.

import java.io.*;
public class MyNumbers   {

      public static void main(String args[] )   {

     int[] numbers = new int[];
     int arraySize = 0;
     int i = 0;
     String response1, response2;
     int arrayValue = 0;
     BufferedReader reader;

     reader = new BufferedReader(new InputStreamReader(System.in));

     System.out.print("Please enter the array size: ");
      try   {
          response1 = reader.readLine();
          arraySize = Integer.parseInt(response1);
          System.out.println("The array size is: " + arraySize);
          reader.close();
          }
     catch (IOException ioe  {
           System.out.println("I/O Exception Occurred");
           }          
      try {
          do {
          System.out.print("Please enter the element value: ");
               response2 = reader.readLine();
               arrayValue = INteger.parseInt(response2);
               i++;
               reader.close();
             }
          while (i<arraySize);
         }
       catch (IOException ioe    {
            System.out.println (I/O Exception Occurred");
         }


         for(i=0; i<arraySize; i++)  {
            System.out.println(numbers[i]);
         }
      }
    }
           
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Question by:Sarah777
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7 Comments
 
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Mayank S earned 250 total points
ID: 16881139
>> public static void main(String args[] )   {

public static void main(String args[] )   throws Exception {
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Expert Comment

by:Mayank S
ID: 16881145
It will help if you can tell what the compilation errors are and at what lines. I guess one of them would be that you did not handle the exception at:

>> reader = new BufferedReader(new InputStreamReader(System.in));

so I suggested you declare main () as throws Exception. Of course, you can also put it in a try/ catch block and catch IOException....
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by:Mayank S
ID: 16881150
>> int[] numbers = new int[];

Leave it as int[] numbers ;
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Expert Comment

by:Mayank S
ID: 16881153
>> arrayValue = INteger.parseInt(response2);

arrayValue[i] = Integer.parseInt(response2);
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by:Mayank S
ID: 16881157
Sorry: numbers[i] = Integer.parseInt(response2);
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Expert Comment

by:mukundha_expert
ID: 16882872
--->  catch (IOException ioe  
one bracket was missing there
       catch (IOException ioe   )

Now it will compime fine, but u will get a runtime error,

--> you are closing the reader and trying to read it the next time
--> numbers array size is not initialized after you get the value

all others are said by mayank,


     reader = new BufferedReader(new InputStreamReader(System.in));

     System.out.print("Please enter the array size: ");
      try   {
          response1 = reader.readLine();
         
          arraySize = Integer.parseInt(response1);
         
          System.out.println("The array size is: " + arraySize);

          numbers = new int[arraySize ] ; // initialize the array

          //reader.close(); this should not be there
          }
     catch (IOException ioe ) {
           System.out.println("I/O Exception Occurred");
           }          
      try {
          do {
          System.out.print("Please enter the element value: ");
               response2 = reader.readLine();
               numbers[i] = Integer.parseInt(response2); // told by mayank
               i++;
               //reader.close();
             }
          while (i<arraySize);
         }
      }
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Expert Comment

by:Mayank S
ID: 16883088
>> numbers array size is not initialized after you get the value

Yes, I missed mentioning after this one:

>> >> int[] numbers = new int[];
>> Leave it as int[] numbers ;

After reading arraySize, make it: numbers = new int[arraySize];
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