Batch script: echo each path in new line

I need a batch script that would echo each path in a new line. So far I have this which echoes all the paths in the same line:

FOR /F "tokens=* delims=;" %%A IN ('ECHO %path%') DO echo %%A

Thanks
gromulAsked:
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gromulAuthor Commented:
Path can have one or more items
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gromulAuthor Commented:
More specifically, 2+
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oBdACommented:
Assuming there are no semicolons in a path statement (it could theoretically happen ...), the following should work:

set Tail=%Path%
:loop
for /f "tokens=1* delims=;" %%a in ("%Tail%") do (
  echo %%a
  set Tail=%%b
  if not "%%b"=="" goto :loop
)
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gromulAuthor Commented:
What do you mean "there are no semicolons in a path statement"? My path (echo %path%) looks something like this:

path1;path2;path3
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oBdACommented:
That's okay, in that case, it's the regular delimiter for the different paths.
But theoretically, a semicolon could be part of a directory path:
%systemroot%\system32;%systemroot%;"C:\Some\Folder\with a ; in it";C:\Program Files\Acme
That's when it gets ugly, because the "for" command wouldn't care about the quotation marks around the directory, and break it up to
%systemroot%\system32
%systemroot%
"C:\Some\Folder\with a
in it"
C:\Program Files\Acme
Not that i can remember having ever come across a folder name with a semicolon in it, and it's even less likely for it to appear in a system's path, but just for the sake of completeness, it should be mentioned ...
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gromulAuthor Commented:
All right. Thanks!
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