ESCALATOR PROBLEM

There is a escalator and 2 persons move down it.A takes 50 steps and B takes 75 steps while the escalator is moving down.Given that the time taken by A to take 1 step is equal to time taken by B to take 3 steps.Find the no. of steps in the escalator while it is staionary

sinha_anshul26Asked:
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alainbrydenConnect With a Mentor Commented:
This is easy after solving the other one.

Let the number of steps = x.
No of steps rolled in by the escalator when A is walking down = x - 50. similarly for B is  x - 75
By the time A walked 1 step, the number of steps removed by the escalator = (x - 50)/50
By the time B walked 3 step, the number of steps removed by the escalator = 3(x - 75)/75
(x - 50)/50  =  3(x - 75)/75
(x - 50)*75 =  3(x - 75)*50
75x - 3750  = 150x - 11520
       75x     =    7500
            x = 100

Q.E.D.
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sinha_anshul26Author Commented:
i know but i need sol to this one
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sinha_anshul26Author Commented:
Hi Alain, Thanks for your quick help,
however I am not able to understand logic of these two equations....

By the time A walked 1 step, the number of steps removed
by the escalator = (x - 50)/50
By the time B walked 3 step, the number of steps removed
by the escalator = 3(x - 75)/75
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sinha_anshul26Author Commented:
ok, it clear now...
Thaks Alain alot.
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