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loading an array

Posted on 2006-06-16
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Last Modified: 2011-09-20
Hi Guys,
            Is it possible to load an array in VB the way itcam be done in C#,

int[] myArray = {1,4,6,7,8,9,0,7};

Thanks
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Question by:Autofreak
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15 Comments
 
LVL 37

Expert Comment

by:Harisha M G
ID: 16923989
Hi,

myArray = Array(1,4,6,7,8,9,0,7)

However, myArray must be of Variant type.



---
Harish
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Author Comment

by:Autofreak
ID: 16924024
What if it's two_dimensional?
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LVL 37

Accepted Solution

by:
Harisha M G earned 200 total points
ID: 16924025
Autofreak, somewhat better if you want to take care of the type also...

    Dim iArray() As Integer
    myarray = Array(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)
    For i = LBound(myarray) To UBound(myarray)
        ReDim Preserve iArray(LBound(myarray) To i)
        iArray(i) = myarray(i)
    Next

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LVL 37

Expert Comment

by:Harisha M G
ID: 16924032
   myarray = Array(Array(1, 2, 3, 4),Array(5, 6, 7, 8),Array(9, 10, 11, 12), _
                    Array(13, 14, 15, 16))
0
 

Author Comment

by:Autofreak
ID: 16924209
Cool
        How do I retrieve myArray(0,1) in one line?? It does't onderstand this syntax.
Thanks
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LVL 37

Expert Comment

by:Harisha M G
ID: 16924218
You told the answer yourself !!

myArray(0,1)

!!
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LVL 37

Expert Comment

by:Harisha M G
ID: 16924228
Oh.. sorry.. you should use

myArray(0)(1)

to get 2 (1st row, 2nd column)

Usually 0,1 is used. However, in this case, we are using a variant to act as an array. So, we should use this syntax.
0
 

Author Comment

by:Autofreak
ID: 16924311
Damn it,
          the functions that recieve the values from the array compalin on argument type mismatch ,
is there a function to convert a variant into a string?

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LVL 86

Expert Comment

by:Mike Tomlinson
ID: 16924404
Are you using VB6 or Vb.Net?
0
 
LVL 37

Expert Comment

by:Harisha M G
ID: 16924409
what exactly are you storing ?
0
 
LVL 37

Expert Comment

by:Harisha M G
ID: 16924426
Idle_Mind, if it were VB.NET, then he could have assigned it directly, as in C#
I think it is VB 6.


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LVL 86

Expert Comment

by:Mike Tomlinson
ID: 16924428
Right...with slight differences in syntax.

I just wanted to be sure.  =)
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LVL 37

Expert Comment

by:Harisha M G
ID: 16924446
:)
0
 
LVL 9

Expert Comment

by:justchat_1
ID: 16924651
if you needed it:
string = CStr(varient)
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Author Comment

by:Autofreak
ID: 16995465
Sorry Guys, So distracted I was, eXcellent tips,

Cheers
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