ian_r
asked on
IF statement execution dependant on record count
I want to perform a series of actions on a table, but only if there are records in the table.
The table name will eventually be passed as parameter to the stored procedure, so the table name in the SELECT COUNT statement can change.
I'm struggling with the syntax and would appreciate some help. I'm getting the following error:
Server: Msg 137, Level 15, State 2, Line 17
Must declare the variable '@tableName'.
I have declared the variable so I must be doing something else wrong. Does anyone have any suggestions on how to fix this, or perhaps a better way to achieve the same thing?
Code being used:
DECLARE @type int, @tableName varchar(200), @numRecords int
SET @type = 7
IF @type = 7
BEGIN
SET @tableName = 'table1'
END
ELSE
BEGIN
SET @tableName = 'table2'
END
SELECT @numRecords= COUNT(*) FROM @tableName
-- only try and transfer records if some exist
IF (@numRecords) > 0
BEGIN
PRINT 'There are records in the table'
END
Try this
DECLARE @type int, @tableName varchar(200), @numRecords int
Declare @SQL varchar(255)
SET @type = 7
IF @type = 7
BEGIN
SET @tableName = 'table1'
END
ELSE
BEGIN
SET @tableName = 'table2'
END
Set @SQL = 'SELECT @numRecords = COUNT(*) FROM [' + @tableName + ']'
Execute (@SQL)
-- only try and transfer records if some exist
IF (@numRecords) > 0
BEGIN
PRINT 'There are records in the table'
END
hongjun
DECLARE @type int, @tableName varchar(200), @numRecords int
Declare @SQL varchar(255)
SET @type = 7
IF @type = 7
BEGIN
SET @tableName = 'table1'
END
ELSE
BEGIN
SET @tableName = 'table2'
END
Set @SQL = 'SELECT @numRecords = COUNT(*) FROM [' + @tableName + ']'
Execute (@SQL)
-- only try and transfer records if some exist
IF (@numRecords) > 0
BEGIN
PRINT 'There are records in the table'
END
hongjun
sorry for the typo, its exec not exes
ASKER
Thanks. The two suggestions look the same to me, and I've just tried the code that hongjun supplied, but I'm now getting the error:
Server: Msg 137, Level 15, State 1, Line 1
Must declare the variable '@numRecords'.
Which is strange because @numRecords is declared. I'll continue to play around with it, unless anyone know's why it's failing?
Maybe I've just been staring at it for too long...
Server: Msg 137, Level 15, State 1, Line 1
Must declare the variable '@numRecords'.
Which is strange because @numRecords is declared. I'll continue to play around with it, unless anyone know's why it's failing?
Maybe I've just been staring at it for too long...
Try this
DECLARE @type int, @tableName varchar(200)
Declare @SQL varchar(255)
SET @type = 7
IF @type = 7
BEGIN
SET @tableName = 'table1'
END
ELSE
BEGIN
SET @tableName = 'table2'
END
Execute ('
Declare @numRecords int
SELECT @numRecords=COUNT(*) FROM ' + @tableName +
'-- only try and transfer records if some exist
IF (@numRecords) > 0
BEGIN
PRINT ''There are records in the table''
END
'
)
DECLARE @type int, @tableName varchar(200)
Declare @SQL varchar(255)
SET @type = 7
IF @type = 7
BEGIN
SET @tableName = 'table1'
END
ELSE
BEGIN
SET @tableName = 'table2'
END
Execute ('
Declare @numRecords int
SELECT @numRecords=COUNT(*) FROM ' + @tableName +
'-- only try and transfer records if some exist
IF (@numRecords) > 0
BEGIN
PRINT ''There are records in the table''
END
'
)
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SOLUTION
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you shouldn't write procedures like this ...
this is a very poor style and requires dynamic sql to provide the result....
which can lead to all sorts of security and performance issues...
you need to re-evaluate your requirements...
what are you actually trying to achieve?
in what circumstance do you need the information?
(dynamic sql can be ok in a System management sense...)
this is a very poor style and requires dynamic sql to provide the result....
which can lead to all sorts of security and performance issues...
you need to re-evaluate your requirements...
what are you actually trying to achieve?
in what circumstance do you need the information?
(dynamic sql can be ok in a System management sense...)
with
declare @sql varchar(8000)
set @sql = 'SELECT @numRecords= COUNT(*) FROM ' + @tableName
exes(@sql)