parse a simple xml file


I would like to parse a simple xml file.
Is this the right way to load it? I will make the file document load dynamic later.

DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();

    // Step 2: create a DocumentBuilder
    DocumentBuilder db = dbf.newDocumentBuilder();

    // Step 3: parse the input file to get a Document object
    Document doc = db.parse(new File(C:\\TEST.XML));

In the following xml file i would like to find default tag that = for example test.

Rename the tag.

Add a tag at the highest and lowest level.

And just how to loop throug the tags to find the one i want. Thanks for any help.

Also delete tags.

- <type>
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FunnyManConnect With a Mentor Commented:
You're on the right track, yes.  Calling doc.getFirstNode() will get you the root Node (tag) of the document.  From there:
node.getChildNodes() -> NodeList of children.
nodelist.getLength() ->  Number of children.
nodelist.item(i) -> Get i-th child of the node (0-based).
node.getNodeName() -> Tag name.
node.getNodeValue() -> Text content of the node.
node.removeChild(n) -> Removes the child node n from node.
node.replaceChild(n1,n2) -> Replaces child node n1 of node with n2.

It looks like Document.renameNode(Node n, String namespaceURI, String qualifiedName) will do renaming for you, but I'm not sure how to use it.

For the record, I have yet to figure out WHY the W3C decided on such a roundabout way of implementing this.  It ought to be possible to get the Document by calling a method like XML.parse(), and then get the children by calling node.getLength() and node.getChild(i), but noooo...
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