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How do you set memory for the OpenFileDialog so that it opens in the same directory as the last time you saved/opened a file?

I was wondering how to set memory for the OpenFileDirectory or SaveFildirectory so that when a file dialog is opened, it opens in the same directory as the last time you used the open file dialog or the same directory as the last time you used the save dialog box.  Any takers?  It's worth 500 big points!  How would I code this in VB.NET For a Windows Form?
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VBBRett
Asked:
VBBRett
1 Solution
 
AlexFMCommented:
Before showing a dialog set it's InitialDirectory property to required value:

dlg.InitialDirectory = directory

When dialog is closed, get directory from it's FileName property:

directory = Path.GetDirectoryName(dlg.FileName)

Use directory for the next call to Open/Save dialog. If you want to keep initial directory persistent, keep it in the Registry or application settings.
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Fernando SotoRetiredCommented:
Hi VBBRett;

I think this will work for you.

After creating the OpenFileDialog or the SaveFileDialog and before doing the ShowDialog methed do this:

OpenFileDialog
        Dim ofd As New OpenFileDialog
        ofd.RestoreDirectory = False
        ofd.ShowDialog()

Save File Dialog
        Dim sfd As New SaveFileDialog
        sfd.RestoreDirectory = False
        sfd.ShowDialog()

Fernando
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