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AIX 4.3 Crontab reached a symbol that is not expected... What now?

Posted on 2006-06-19
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Last Modified: 2013-11-17
I am trying to add a line into cron. I want to check my print queue status every minute and if one is down, I want it to push it back up. So I entered this into crontab...

"0-59/1 * * * enq -WAs | grep $(dspmsg -s 2 qstat 33) | cut -d' ' -f1 | xargs enablek"

And AIX returned this error...

"/tmp/crontab_qKbUa" 1 line, 85 characters
A line of the crontab file:
        0-59/1 * * * enq -WAs | grep $(dspmsg -s 2 qstat 33) | cut -d' ' -f1 | xargs enablek

contains the following error:
        0481-079 Reached a symbol that is not expected.

I do not know enough about cron to figure this one out myself. Thanks for any help in advance!
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Question by:_SKIN_
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2 Comments
 
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Accepted Solution

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enyamada earned 200 total points
ID: 16935674

Hi,

AIX cron does not accept the / notation. If you want to run every single minute the script, try

* * * * * enq -WAs | grep $(dspmsg -s 2 qstat 33) | cut -d' ' -f1 | xargs enablek

instead.

Good luck.
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Author Comment

by:_SKIN_
ID: 16936370
Thanks, that worked.
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