Solved

Looping through XML Data

Posted on 2006-06-20
10
365 Views
Last Modified: 2010-04-07
Hello XML'ers
Got a question today.  I have an XML File that i am writing a vba application to manipulate.  I am having difficulty traversing the childnodes.
Here is the xml AND THE VBA.
Thanks Ahead of time,
Dim myXML As New MSXML2.DOMDocument
    Dim myXElem As MSXML2.IXMLDOMElement
    Dim myXRecord As MSXML2.IXMLDOMElement
    Dim myXField As MSXML2.IXMLDOMElement
    Dim myXEntry As MSXML2.IXMLDOMEntity
    Dim oElSta() As String
   
   
    myXML.async = False
    myXML.validateOnParse = False
    myXML.Load ("W:\Bridge Inspection\Special Inspection - Drawings\UW - Drawings\Bridge_Scour.xml")
   
    Set myXElem = myXML.documentElement
    For Each myXRecord In myXElem.childNodes
        Debug.Print "========SOMETHING======"
        Debug.Print "BaseName " & myXElem.baseName  'Bridge_Scour
        Debug.Print "Structure Name " & myXRecord.Attributes(0).nodeValue
        For Each myXField In myXRecord.childNodes
            Debug.Print "Year " & myXField.Attributes(0).nodeValue
            'Debug.Print myXField.baseName & "---" & myXField.Text
            'Debug.Print "Stations and Elevations " & myXField.Text
'            Debug.Print myXField.childNodes(0).baseName 'Survey
'            Debug.Print myXField.childNodes(0).childNodes(0).firstChild.baseName 'Station Text
'            Debug.Print myXField.childNodes(0).childNodes(0).lastChild.baseName  'Elevation
            oElSta = Split(myXField.Text, " ")
            'Loop through the stations and elevations of the years
            For i = 0 To myXField.childNodes.Length
                Debug.Print myXField.childNodes(0).childNodes(0).firstChild.baseName & " " & myXField.childNodes(0).firstChild.childNodes(i).Text 'Station Te
                Debug.Print myXField.childNodes(0).childNodes(0).lastChild.baseName & " " & myXField.childNodes(0).firstChild.childNodes(1).Text 'Elevation
            Next
           
'            For i = 0 To UBound(oElSta)
'                Debug.Print oElSta(i)
'            Next
        Next
       
    Next
End Sub


I WANT TO LOOP THROUGH THE STATION AND ELEVATION EACH AT THEIR OWN LINE


<?xml version="1.0"?>
<!DOCTYPE Bridge_Scour SYSTEM "Bridge_Scour.dtd">
<Bridge_Scour>
     <Structure Name = "uw1.dgn">
          <Surveys year="2000">
                <Survey>
                    <Entry><Station>0.1</Station> <Elevation>123.45</Elevation></Entry>
                    <Entry><Station>0.2</Station> <Elevation>123.46</Elevation></Entry>
               </Survey>
          </Surveys>
          <Surveys year="2001">
                <Survey>
                    <Entry><Station>0.3</Station> <Elevation>123.47</Elevation></Entry>
                    <Entry><Station>0.4</Station> <Elevation>123.48</Elevation></Entry>
               </Survey>
          </Surveys>
     </Structure>
     <Structure Name = "uw2.dgn">
          <Surveys year="2001">
                <Survey>
                    <Entry><Station>0.5</Station> <Elevation>123.49</Elevation></Entry>
                    <Entry><Station>0.6</Station> <Elevation>123.50</Elevation></Entry>
               </Survey>
          </Surveys>
     </Structure>
</Bridge_Scour>
0
Comment
Question by:sherrick123
  • 3
  • 3
10 Comments
 
LVL 52

Expert Comment

by:Carl Tawn
ID: 16942900
My, thats a tough bit of reading :o)

What output are you wanting ? Its probably easier, and cleaner, to use the SelectNodes and SelectSingleNode methods to retrieve the data you want rather than trying to traverse nested childNodes collections.
0
 
LVL 17

Expert Comment

by:inthedark
ID: 16943401
Is space allowed between name an value

<Structure Name = "uw1.dgn">

try to

<Structure Name="uw1.dgn">

Appart from that the data looks ok.
0
 

Author Comment

by:sherrick123
ID: 16943445
I want the Station and Elevation data
0
Independent Software Vendors: We Want Your Opinion

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

 
LVL 52

Expert Comment

by:Carl Tawn
ID: 16943741
I mean't more along the lines of what data do you need from the overall document. You have a lot of Debug statements so I was wondering if you were just outputting them because you could, or if you actually need them all.
0
 

Author Comment

by:sherrick123
ID: 16944089
okay,  sorry about that.
What i am really needing is that for a particular year for a particular structure i want the station and elevation data.
its a one to many relationship.  for One Structure their will be Many Years and for Each Year their of corse be many Station and Elevations.

So in the end I want to populate a list box of Structures.
The user Pics a structure Then a list box will be populated with the Years
The User then Pics the years and Then a datagrid will be populated with the
Station and elevation.  

This is my first time with XML and I am just figuring the Nodes and ChildNodes and the navigation of the XML file

Thanks
0
 
LVL 52

Accepted Solution

by:
Carl Tawn earned 500 total points
ID: 16944301
Ok, gotcha.

Generally speaking, unless you are working with a very simple structure (no more than one or two levels deep) then using the childNodes collection is a bit cumbersome. Hopefully this sample for your problem will demonstrate a simpler mechanism:

    '// Assuming sName = "uw1.dgn" and sYear = "2001"

    Dim myXML As New MSXML2.DOMDocument
    Dim oSurvey As MSXML2.IXMLDomNodeList
    Dim oNode As MSXML2.IXMLDomNode
    Dim oElSta() As String
   
    myXML.async = False
    myXML.validateOnParse = False
    myXML.Load ("W:\Bridge Inspection\Special Inspection - Drawings\UW - Drawings\Bridge_Scour.xml")

    '// Grab all Entry nodes for the Year we are interested in
    Set oSurvey = myXML.SelectNodes("Bridge_Scour/Structure[@Name='" & sName & "']/Surveys[@year='" & sYear & "']/Survey/Entry")

    '// Check that we got something
    If Not oSurvey Is Nothing Then
        Debug.Print "Found " & oSurvey.Length & " matches"
        '// Loop through each node and retrieve Station and Elevation
        For Each oNode In oSurvey
            Debug.Print "Station: " & oNode.ChildNodes(0).Text
            Debug.Print "Elevation: " & oNode.ChildNodes(1).Text
        Next oNode
    End If
0
 

Author Comment

by:sherrick123
ID: 16944594
oh now that was alot easier than what i was trying to do.  I think i will be able to incorporate some of my code into yours and have everything work just fine.

Thanks so much
0

Featured Post

Technology Partners: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

I was working on a PowerPoint add-in the other day and a client asked me "can you implement a feature which processes a chart when it's pasted into a slide from another deck?". It got me wondering how to hook into built-in ribbon events in Office.
Since upgrading to Office 2013 or higher installing the Smart Indenter addin will fail. This article will explain how to install it so it will work regardless of the Office version installed.
Get people started with the process of using Access VBA to control Outlook using automation, Microsoft Access can control other applications. An example is the ability to programmatically talk to Microsoft Outlook. Using automation, an Access applic…
Get people started with the process of using Access VBA to control Excel using automation, Microsoft Access can control other applications. An example is the ability to programmatically talk to Excel. Using automation, an Access application can laun…

735 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question