Javascript : InputFile.Click() Access is denied.

HI everyone ,

What should be happening :

When you select a product from the listbox, a File selection window will open to select an image for that product. So far, when i select a product, the file selection window is opened, once i have selected a file, i click open and then i get an Access is Denied error for calling submit_NewFreeItem() with the "onpropertychange" event from the File input.  

Take notes that if i click the Browse button from the Input File and select a file, everything works fine, the script calls the submit click. But when i call the Browse button from a script .click() it gives me this Access is denied error.

Thanks for checking it out,

Here is the partial code for this error :

<script language="javascript">
               
                function submit_NewFreeItem()
      {
            document.all.submitNewFreeItem.click();
      }
      function NewFreeItem_Click()
      {
            document.all.NewFreeItem.click();
      }
</script>

...

<select name='ProductToAdd' onchange='NewFreeItem_Click()'>
<option value='0' selected>No Product Selected</option>
<option value='1'>Test</option>
</select>

<INPUT type=file id="NewFreeItem" name="NewFreeItem" onpropertychange="submit_NewFreeItem()">

<INPUT type="submit" style="display:none" name="submitNewFreeItem" id="submitNewFreeItem" value="submitNewFreeItem">


...
darkbenAsked:
Who is Participating?
 
RoonaanConnect With a Mentor Commented:
That is correct. You also cannot access the "value" property and other properties of the fileinput field. As part of the browsers security settings. Cannot be overridden though.

-r-
0
 
darkbenAuthor Commented:
Any of you have a workaround for this ? :(
0
 
RoonaanCommented:
No.

-r-
0
 
darkbenAuthor Commented:
Even tho i tried putting all browser security to the lowest, still doesnt work.

So your telling me there is no way i can auto submit my form after the file selection when the file selection has been poped with a script ?
0
 
RoonaanCommented:
You can try form.submit().

-r-
0
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