asked on

Script to change CR LF to LF -- 0D 0A to 0A

I'm trying to get a script written to change the carrige return linefeed characters to linefeed characters

I have a file where all lines end with Hex 0D 0A I want them to end with 0A

I tried using sed to do a search and replace - something like this:

sed -e 's/\x0D/whatever/' test.txt > test.new

Search for 0d and replace with "whatever"

I just wanted to get this working first - Anyway - sed runs without error but apparetnly can't find any 0D in my file
even though I know the hex character exists.

Thanks

jkr

Don't reinvent the wheel, 'recode' or 'dos2unix' can do that, e.g.

dos2unix test.txt test.new

recode ibmpc..lat1 text.txt > test.new

aflat362

ASKER

I don't have either of those executables . . .

[x67167] dbimg1:/home/x67167) dos2unix
ksh: dos2unix: not found.
[x67167] dbimg1:/home/x67167) recode
ksh: recode: not found.

aflat362

ASKER

I'm running AIX 5.2 ml 4

ASKER CERTIFIED SOLUTION

ravenpl

membership

This solution is only available to members.

To access this solution, you must be a member of Experts Exchange.

Start Free Trial

aflat362

ASKER

hmm.

I don't have perl installed.

I'd like to get this working with the tools I have:

shell (korn, bourne or C)
awk
sed

Thanks for the posts.

aflat362

ASKER

nevermind. I do have perl.

This may work for me.

cat test.txt | perl -ne 'y/\r//d; print' > test.new

Can you explain what the y/\r//d; part of this command is doing?

or point me to a reference?

Thanks

ravenpl

cat file.txt | sed -e 's/\r//'
#but please verify that it in fact removes the char...

ravenpl

Bots, sed and perl s/// or y///d searches for given character, then rplaces with replaement char(or removes if no replacement found
y/ab/c/d # changes each occurance of 'a' to 'c' and remoes any 'c'.

ravenpl

removes any 'b' character - dorry for mistake above.

aflat362

ASKER

Ok, so for this example it searches for \r which must equate to 0D 0A and replaces it with what? null?

what's up with the "d"?

cat test.txt | perl -ne 'y/\r//d; print' > test.new

Thanks

ravenpl

in fact - not really. It searched for any \r and removes. 'd' stands for delete found but not replaced characters.
For more please see: man perlop, operation 'tr' or 'y'

aflat362

ASKER

Thanks!