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Posted on 2006-06-21
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Last Modified: 2010-03-05
I have
$output = "X123456 X234567 X234568
X123452 X234562 X234561
X123422 X234533 X234522";

how can i grep only the 5 digits and save it in array @codeword

can i do using map?
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Question by:perlperl
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12 Comments
 

Author Comment

by:perlperl
ID: 16954737
i tired

@output = split (/ /, $output);
my @codeword = map { /(X\d{5})/ } @output;

teh output i get, is
234567 234568 234562 234561 234533 234522


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Author Comment

by:perlperl
ID: 16954742
sorry the output was
123456 234567 234568 234562 234561 234533 234522


it skips the first element forn second row onwards
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LVL 37

Accepted Solution

by:
Harisha M G earned 2000 total points
ID: 16954849
Hi,

try

@output = split (/\s/, $output);


---
Harish
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Author Comment

by:perlperl
ID: 16954893
if i try  \s

teh output i get is
234567 234568  123452 234562 234561 1231422 234533 234522

i get everything except the first elemnt 123456


just clarification, i m using
my @codeword = map { /(X\d{6})/ } @output;


there was typo above where i specified 5
0
 

Author Comment

by:perlperl
ID: 16954900
this worked fine but i don't like this format

@output = split(/\n/,$output);
for($i = 0; $i < @output; $i++) {
 @code = split(/ /, $output[$i]);
 @c = map { /(X\d{6})/ } @code;
@subset_ucode = ( @subset_ucode ,@c);
}
print "@subset_ucode \n";
0
 
LVL 37

Expert Comment

by:Harisha M G
ID: 16954918
I got this:
X12345 X23456 X23456 X12345 X23456 X23456 X12342 X23453 X23452


the code was:

$output=  "X123456 X234567 X234568
X123452 X234562 X234561
X123422 X234533 X234522";

@output = split (/\s/, $output);
@codeword = map { /(X\d{5})/ } @output;

print "@codeword";

If you want the digits, then change

@codeword = map { /(X\d{5})/ } @output;

to

@codeword = map { /X(\d{5})/ } @output;
0
 

Author Comment

by:perlperl
ID: 16954938
oops sorry my bad...

that works
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Author Comment

by:perlperl
ID: 16954945
why \s worked.
can u pls explain
0
 
LVL 37

Expert Comment

by:Harisha M G
ID: 16954949
\s means whitespace. It includes space, tab and newline character
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Author Comment

by:perlperl
ID: 16954958
Got it!!!

Thanks a lot
0
 
LVL 8

Expert Comment

by:Perl_Diver
ID: 16955028
$output = "X123456 X234567 X234568
X123452 X234562 X234561
X123422 X234533 X234522";

@codeword = $output =~ /(\d+)/g;

print "@codeword";

0
 
LVL 84

Expert Comment

by:ozo
ID: 16965246
what exactly do you want in @codeword?  you say you want only the 5 digits, but everything in $output  looks like it has 6 digits
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