setting a one off cron job in crontab

Hi,

The above will run at 7:45PM on the 25 of the month June you could change it to the following:

45  19  0  0  0  /opt/utils/sendMesg.sh

The above should run at 7:45PM every sunday

Opps I should of put:

45  19  *  *  0  /opt/utils/sendMesg.sh

Thanks for the quick reply. I'm sure I read somewhere that the 3 and 5th fields are OR'd, so would your solution not run tomorrow night at 7.45pm as well?

If you want to run the job only one time, you should use the "at" command.
Only use cron if you want your job to run more than once (eg. each 25th of month, each day at 1 am, ...)

As mentioned by JulieBouillon, you should use 'at' if this is a one off command. cron is for repeated tasks.

at -f mytask 18:30

Will run the tasks in the file "mytask" at 18:30

Tasks need to be 1 per line in the mytask file.

You will probably need to create the file:

/etc/at.allow

and add your username to it if you want to run 'at' as any user other than root.

man at

is worth a read if you wish to be able to examine tasks in the 'at' queue.

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>in the crontab will sendMesg.sh this year at 19:45 on 25 Jun, and also 19:45 on 25 Jun next year, the year after and so on.

Ooops - slight mistake -- It will only run in a year where 25 Jun is a Sunday! Change the 0 to a * for every year!

http://www.adminschoice.com/docs/crontab.htm#Crontab%20file

for crontab syntax.

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Hi joel1976,

*     *   *   *    *  command to be executed
-     -    -    -    -
|     |     |     |     |
|     |     |     |     +----- day of week (0 - 6) (Sunday=0)
|     |     |     +------- month (1 - 12)
|     |     +--------- day of month (1 - 31)
|     +----------- hour (0 - 23)
+------------- min (0 - 59)