Solved

# How to calculate an absolute position/rotation given a relative position/rotation and a parent position/rotation vector and vice versa?

Posted on 2006-06-23
1,372 Views
I'm making an application where I need to be able to calculate an absolute position/rotation given a relative position/rotation and a parent position/rotation it is relative to. The order of rotation will be X, Y then Z. I also need to be able to go the opposite way. That is finding a relative position/rotation given an absolute position/rotation and a parent position/rotation. What is the most efficient and easiest way to integrate this in an application that uses position and rotation vectors (radians) to store object placements?

If I'm not too wrong I can rotate it by X by multiplying the relative position X with cos(rotation x) and relative position Y with cos(rotation x). Not sure about Y and Z rotation though. I'm thankful for any solution :).
0
Question by:imnotapro
• 3
• 3

LVL 25

Expert Comment

Absolute parent position: vector P.

To rotate a vector around an axis by an angle 'a', you multiply the vector with the appropriate matrix:

Rotate around X axis:

[ 1     0        0    0 ]
[ 0  cos a  sin a  0 ]
[ 0 -sin a  cos a  0 ]
[ 0     0        0    1 ]

Rotate around Y axis:

[ cos a  0 -sin a   0 ]
[    0     1    0      0 ]
[ sin a   0  cos a  0 ]
[    0     0    0      1 ]

Rotate around Z axis:

[ cos a  sin a  0  0 ]
[-sin a  cos a  0  0 ]
[    0        0    1  0 ]
[    0        0    0  1 ]

You need to watch out for what is known as "Gimbal lock", where one or more of the rotations have no effect due to the order in which you perform the rotation.

To find the angle between two vectors around each axis, treat each vector as being 3 different 2D vectors, and use the dot product:

For vectors u and v:

u dot v = u.x * v.x + u.y*v.y + .. = |u| * |v| * Cos a

Therefore:

a = arccos( u dot v / (|u| * |v|) )
0

Author Comment

I get the logic in what you're saying, but I think I need an example. Say the parent position vector is called p (p.x p.y and p.z). The parent rotation vector is called pr (pr.x pr.y and pr.z). Then we have a child position vector that is relative to the parent position and rotation (c.x c.y and c.z) and a child rotation vector cr (cr.x cr.y and cr.z). I know nothing about matrices. How would you step for step go to find the child absolute position and rotation (a.x a.y a.z and ar.x ar.y ar.z)?

Also say we have the child absolute position/rotation (a and ar) and the parent absolute position/rotation (p and pr). Any example on how to find the child relative position/rotation (c and cr)?

I'm a programmer and I'm not very experienced on vector math and matrix math so I need it step for step :). Thanks!
0

LVL 25

Expert Comment

I'll be happy to provide an example; but, what do you mean by "rotation vector" ?
0

Author Comment

A vector with 3 floats defining the rotation of the mesh in radians. One for X axis, one for Y and one for Z. Ie  pi/2,0,0 is 90 degrees along the X axis.
0

LVL 25

Accepted Solution

InteractiveMind earned 250 total points
Oh, ok.

Well, to multiply a vector with a matrix, you must first extend the vector to a 4x1 matrix, giving the 4th element (w) the value of 1.

So the vector V, becomes:

[ V.x ]
[ V.y ]
[ V.z ]
[   1  ]

(This is just another notation for what you've used above:  (V.x, V.y, V.z, 1)).

To then multiply this with a 4x4 matrix (which all of the transformation matrices are), let's take the following matrix as an example:

[ a  b  c  d ]
[ e  f   g  h ]
[ i   j   k  l  ]
[ m n  o  p ]

You multiply each row with the vectors column, and sum those components. So you get the following as the result:

[ a*V.x  + b*V.y + c*V.z + d ]
[ e*V.x  + f*V.y  + g*V.z + h ]
[ i*V.x   + j*V.y  + k*V.z + l  ]
[ m*V.x + n*V.y + o*V.z + p ]

And with the transformation matrices, the last row in that result can be neglected. So your new, transformed vector, becomes just:

[ a*V.x  + b*V.y + c*V.z + d ]         // x component
[ e*V.x  + f*V.y  + g*V.z + h ]        // y component
[ i*V.x   + j*V.y  + k*V.z + l  ]        // z component

And that's your transformed vector! :)
0

Author Comment

Okay, I've written up some code using the example you provided and I'm about to test it once I have a way of doing this the other way around. To get the relative position using parent position, parent rotation and child absolute position/rotation I guess I have to unrotate the child first using the absolute rotation of the child and the absolute rotation of the parent? Would it work taking the difference between those rotations (child absolute rotation minus parent absolute rotation), make them negative and then rotate them using what you said above?
0

LVL 1

Assisted Solution

lawyerboy780 earned 250 total points
I'm confused.  Can anything be absolutely located if all or any  attempts at imposing order result in a systemic increase in chaos?  You know the entropy is inversely related to enthalpy thing?
0

## Featured Post

### Suggested Solutions

springs 17 43
How does LINEST operate in Microsoft Excel ? 5 63
Simplify expression 3 68
Exam question 48 99
A Guide to the PMT, FV, IPMT and PPMT Functions In MS Excel we have the PMT, FV, IPMT and PPMT functions, which do a fantastic job for interest rate calculations.  But what if you don't have Excel ? This article is for programmers looking to re…
Introduction On a scale of 1 to 10, how would you rate our Product? Many of us have answered that question time and time again. But only a few of us have had the pleasure of receiving a stack of the filled out surveys and being asked to do somethi…
Excel styles will make formatting consistent and let you apply and change formatting faster. In this tutorial, you'll learn how to use Excel's built-in styles, how to modify styles, and how to create your own. You'll also learn how to use your custo…
When you create an app prototype with Adobe XD, you can insert system screens -- sharing or Control Center, for example -- with just a few clicks. This video shows you how. You can take the full course on Experts Exchange at http://bit.ly/XDcourse.