asked on

char* array

I have this code

char DataPacket[128];
SocketObject ClientSocketObject;

iBytesReceived = ClientSocketObject.Recv(&DataPacket, 128, 0);

and, Recv is defined as,

int SocketObject::Recv( char *szBuffer, int iBufLen, int iFlags)
{
...
}

I'm using Visual Studio.Net 2005,

and when i compile,
i get this error

error C2664: 'SocketObject::Recv' : cannot convert parameter 1 from 'char (*__w64 )[128]' to 'char *'
1> Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast

However, this error goes away if i do,

iBytesReceived = ClientSocketObject.Recv(&DataPacket[0], 128, 0); isntead of
iBytesReceived = ClientSocketObject.Recv(&DataPacket, 128, 0);

and I was wondering if this is the correct way to solve the error. Any explnation will be appreciated. I belive this error does not occur in the old Visual C++ compilers.

Thank you very much

ASKER CERTIFIED SOLUTION

clockwatcher

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DanRollins

clockwatcher is correct...

If you have an array...
char DataPacket[128];
then...
DataPacket[0] is a single char (the first one in the array)
&DataPacket[0] is a pointer to a char (char*)
(the same as.... )
DataPacket is a pointer to char (char*)
(however...)
&DataPacket is a pointer to that pointer (it's a char**)

The prototype requires a pointer-to-char, so either of these will work:
&DataPacket[0]
DataPacket

patti_nyl

Hi!

Remove the & sign!

will result to this
iBytesReceived = ClientSocketObject.Recv(DataPacket, 128, 0);

Patrik