I need to receive XML from a C# program using HTTP POST

Hi,

A program written in C# wants to send me some data in XML format using HTTP POST so I need a HTTP server implementation to handle that.
It seems like Indy TidHttpServer / OnCommandOther could be used to it but since I'm under a very tight schedule, I really don't have the time to investigate it.

A solution that shows how to use Indy to receive a XML document from a C# client using HTTP POST and save it to a file, is what I'm looking for..

I'm using Delphi 6 and would prefer to use the Indy version supplied with that if possible.

Cheers,
Lars
LVL 7
BlackManAsked:
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atul_parmarCommented:
1. Drop a TidHttpServer component
2. On the form create event set
    IdHTTPServer1.DefaultPort := 80; // the port where your C# app will connect
    IdHTTPServer1.Active := True;
3. write the following code to the IdHTTPServer1CommandGet event of TidHttpServer component
   var
     xmlText : TStringList;
   begin
    if ARequestInfo.Command = 'GET' then
    begin
      xmlText := TStringList.Create;
      xmlText.LoadFromFile(XMLFileName);
      AResponseInfo.ContentText := xmlText.Text;
      xmlText.Free;
    end;
  end;

0
BlackManAuthor Commented:
Hi,

You solution is the other way around - someone GETTING a XML file from me.
I need to receive the XML (via POST) from someone else.

Cheers,
Lars
0
atul_parmarCommented:
Well, do this.

var
  s : TStringList;
begin
  IdHTTP1.Port := 80; // port number of the server
  IdHTTP1.Connect;
  s := TStringList.Create;
  memo1.Text := IdHTTP1.Post('localhost', s);
  s.Free;
end;
0
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BlackManAuthor Commented:
Sorry, it is still not what I'm looking at..

I need my program to act as a webserver RECEIVING xml-files, so I need to somehow hook into the POST event and save the xml data that are sent to me.
Actually, you can use your last code as a test client when you have made the other end :)

Cheers,
Lars
0
atul_parmarCommented:
Mate the first post will work for you by just changing the GET to POST. e.g.

1. Drop a TidHttpServer component
2. On the form create event set
    IdHTTPServer1.DefaultPort := 80; // the port where your C# app will connect
    IdHTTPServer1.Active := True;
3. write the following code to the IdHTTPServer1CommandGet event of TidHttpServer component
   begin
    if ARequestInfo.Command = 'POST' then
    begin
       ARequestInfo.Document >>>>>>>>> will contain the stuff you need
    end;
  end;
0

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BlackManAuthor Commented:
Ah, I'll check that out - I got confused by the name of the event (OnCommandGet), thought it would only fire on GET operations..

I'll let you know later, thanks..

Cheers,
Lars
0
BlackManAuthor Commented:
Just tried it..

RequestInfo.Command just contains a "/" but it seems like my XML is in RequestInfo.UnparsedParams. Unfortunately, it is "encoded" like this
"'<'#0'?'#0'x'#0'm'#0'l'#0' '#0'v'#0'e'#0'r'#0's'#0'i'#0'o'#0'n'#0'='#0'"'#0'1'#0'.'#0'0'#0'"'#0' '#0'e'#0'n'#0'c'#0'o'#0'd'#0'i'#0'n'#0'g'#0'='#0'"'#0'U'#0'T'#0'F'#0'-'#0'8'#0'"'#0'?'#0'>'#0'<'#0'B'#0'a'#0's'#0'e'#0' '#0'/'#0'>'#0"

Don't know if that is unicode but how do I get the "plain" XML out of it  - and is UnparsedParams really the way to go?


Cheers,
Lars
0
atul_parmarCommented:
It will be in RequestInfo.Document
0
atul_parmarCommented:
The RequestInfo.UnparsedParams contains the url encoded http header. to get the plain text header info use params property.
0
BlackManAuthor Commented:
I'm sorry, I made a mistake in my previous mail..
RequestInfo.Document = '/'  (command is 'POST' of course)

Let me check the code from the C# guy to make sure that they actualle are submitting something valid.

Cheers,
Lars
0
BlackManAuthor Commented:
atul_parmar,

Sorry for the late reply - have been on vacation. I'll work with the C# guys next week and let you know the result.

Cheers,
Lars
0
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