TCP Chat with Rooms
Hi guys, little problem with my Chat application.
For introduction, I got my chat working (execpt for 2-3 exception popping on immediate window, but thats for later)
Before I wrote a specific private sub, When I was opening for example: Room 1 and 3, then writing "Test" in Room 1, the message after pressing the button Send was going at Room 1 AND 3.
So it seems that the message would go everywhere. I fix that with a little compare with : ok if the Sender room is equals to the receiver room then Write the message, else do not. But it is quite cheating: Its fine for 3 rooms, but If We have 500 rooms or even 4000 , it will just lag as hell.
So my problem goes as follow: The message needs to stay at the Right Room. That meens what? When I create my SocketClient, Do I have to change the port ? So each table would have uniquely chats ?? (I GUESS NOT)
Or Do I have to create multiple TCPListener ? (I guess not..)
My Room_Load goes as follow:
Private mobjClient As TcpClient
...
Private Sub frmRoom_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
mobjClient = New TcpClient("localhost", 5000)
mobjClient.GetStream.Begin
Send(username + " as joined. " + CStr(tableID))
End Sub
Ok so here I create a new TcpCLient each time a room is going open, always on port 5000.
What do I have to do to fic the problem of the message needs to stay at the right place ?
thank you
Phil
For introduction, I got my chat working (execpt for 2-3 exception popping on immediate window, but thats for later)
Before I wrote a specific private sub, When I was opening for example: Room 1 and 3, then writing "Test" in Room 1, the message after pressing the button Send was going at Room 1 AND 3.
So it seems that the message would go everywhere. I fix that with a little compare with : ok if the Sender room is equals to the receiver room then Write the message, else do not. But it is quite cheating: Its fine for 3 rooms, but If We have 500 rooms or even 4000 , it will just lag as hell.
So my problem goes as follow: The message needs to stay at the Right Room. That meens what? When I create my SocketClient, Do I have to change the port ? So each table would have uniquely chats ?? (I GUESS NOT)
Or Do I have to create multiple TCPListener ? (I guess not..)
My Room_Load goes as follow:
Private mobjClient As TcpClient
...
Private Sub frmRoom_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
mobjClient = New TcpClient("localhost", 5000)
mobjClient.GetStream.Begin
Send(username + " as joined. " + CStr(tableID))
End Sub
Ok so here I create a new TcpCLient each time a room is going open, always on port 5000.
What do I have to do to fic the problem of the message needs to stay at the right place ?
thank you
Phil
ASKER
Hi Bob,
1) Im using Visual Studio 2005
2) Well I have 1 project for the Server (wich has a form and 1 class) (The Listener)
And another prjoect for the Main app (client) , wich in the form frmRoom is the chat.
in this form i got all the code for client as you probably know.
in frmMain I got a list of room available. if the user Dbl-click on one, well it pops the clicked frmRoom.
I am actually using alot of this sample of Microsoft:
http://msdn.microsoft.com/library/default.asp?url=/library/en-us/dnadvnet/html/vbnet08282001.asp
1) Im using Visual Studio 2005
2) Well I have 1 project for the Server (wich has a form and 1 class) (The Listener)
And another prjoect for the Main app (client) , wich in the form frmRoom is the chat.
in this form i got all the code for client as you probably know.
in frmMain I got a list of room available. if the user Dbl-click on one, well it pops the clicked frmRoom.
I am actually using alot of this sample of Microsoft:
http://msdn.microsoft.com/library/default.asp?url=/library/en-us/dnadvnet/html/vbnet08282001.asp
Does each room get a single instance of a TcpClient? Or is it shared among rooms?
Bob
Bob
ASKER
Private mobjClient As TcpClient
Private Sub frmRoom_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
mobjClient = New TcpClient("localhost", 5000)
mobjClient.GetStream.Begin
Send(username + " as joined. " + CStr(tableID))
End Sub
I am creating a new TcpClient on each room that is going to Open. The same user cannot open the same room twice.
He needs to close it first then re-open.
Private Sub frmRoom_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
mobjClient = New TcpClient("localhost", 5000)
mobjClient.GetStream.Begin
Send(username + " as joined. " + CStr(tableID))
End Sub
I am creating a new TcpClient on each room that is going to Open. The same user cannot open the same room twice.
He needs to close it first then re-open.
You could have a Hashtable that stores the room # and the room form instance, so that you could quickly look up the corresponding form when you need to send a message to a specific room.
Bob
Bob
ASKER
a Hashtable in the chat form? (frmRoom) ?
In my Server side, I am doing something with the Hashtable.:
Private mcolClients As New Hashtable
Private Sub DoListen()
Try
mobjListener = New TcpListener(5000)
mobjListener.Start()
Do
Dim x As New Client(mobjListener.Accept
AddHandler x.Connected, AddressOf OnConnected
AddHandler x.Disconnected, AddressOf OnDisconnected
AddHandler x.LineReceived, AddressOf OnLineReceived
mcolClients.Add(x.ID, x)
Dim params() As Object = {"New connection"}
Me.Invoke(New StatusInvoker(AddressOf Me.UpdateStatus), params)
Loop Until False
Catch
End Try
End Sub
In my Server side, I am doing something with the Hashtable.:
Private mcolClients As New Hashtable
Private Sub DoListen()
Try
mobjListener = New TcpListener(5000)
mobjListener.Start()
Do
Dim x As New Client(mobjListener.Accept
AddHandler x.Connected, AddressOf OnConnected
AddHandler x.Disconnected, AddressOf OnDisconnected
AddHandler x.LineReceived, AddressOf OnLineReceived
mcolClients.Add(x.ID, x)
Dim params() As Object = {"New connection"}
Me.Invoke(New StatusInvoker(AddressOf Me.UpdateStatus), params)
Loop Until False
Catch
End Try
End Sub
From the main form (frmMain), you create an instance of a frmRoom. In frmMain, you could create an instance of the form, and store it like this:
Private m_hashRooms As New Hashtable
...
Dim frm As New frmRoom(roomNumber)
m_hashRooms.Add(roomNumber
Bob
Private m_hashRooms As New Hashtable
...
Dim frm As New frmRoom(roomNumber)
m_hashRooms.Add(roomNumber
Bob
ASKER
I see. Okai, im just not sure how it could help when the boy clicks on the Send button to ship his message.
im sure you're right, but I cant see the light
im sure you're right, but I cant see the light
>>but If We have 500 rooms or even 4000 , it will just lag as hell.
Describe what you mean by this?
Bob
Describe what you mean by this?
Bob
ASKER
Ok,
If the application wasnt comparing the RoomID just before writing the chat text, All rooms would receive the message of any room. Not good.
What I did, is that I did a compare of the RoomID from the btn_Send_CLick then I compare this to the Room of the user.
Then I fix the problem. but NOT completely because I by-pass the problem. You see, If there is 4000 Rooms open, the app will compare 4000 times. Its absolutly not the beat approach. Im sure of that
SO I need to fix that in a way so the Application will not compare, but already know that the Message is for example Room 2 and only send the mesage to all the Rooms 2 opened. (and not compare all rooms to see if it is 2)
If the application wasnt comparing the RoomID just before writing the chat text, All rooms would receive the message of any room. Not good.
What I did, is that I did a compare of the RoomID from the btn_Send_CLick then I compare this to the Room of the user.
Then I fix the problem. but NOT completely because I by-pass the problem. You see, If there is 4000 Rooms open, the app will compare 4000 times. Its absolutly not the beat approach. Im sure of that
SO I need to fix that in a way so the Application will not compare, but already know that the Message is for example Room 2 and only send the mesage to all the Rooms 2 opened. (and not compare all rooms to see if it is 2)
ASKER CERTIFIED SOLUTION
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ASKER
Ok know I think i undestand what you mean..
Yes you're right, i think its the only way.
Thank you Bob
Yes you're right, i think its the only way.
Thank you Bob
1) .NET version? 2002, 2003, 2005?
2) What is the model for the application? Multiple sender classes, multiple receiver classes, main form?
Bob