Problem in creating a service

Posted on 2006-06-28
Last Modified: 2010-05-18
Hey experts,

 I am changing a small section in the code of huge java web application (based on struts & EJBs), and I am having a problem in a service creation. This piece of code:

PreferencesManager preferencesManager = null;
preferencesManager = (PreferencesManager)BusinessServiceFactory.getInstance().createService("",

is working fine in several places of the application, but when I tried to call it from a class of mine, it caused a ServiceNotFoundException (due to an Invocation Target Exception - trying to call the create method); why do you think a service creation would be successful in a class of the application and won't work in a class of mine??
Question by:mte01
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 4
  • 2
LVL 35

Expert Comment

ID: 17000283
It might be a classloader issue. Can you post the full stack trace?

Author Comment

ID: 17000340
2006-06-28 15:12:55,546 ERROR SessionBeanServiceFactory - (create) InvocationTargetException caught while invoking the create() method on the home interface. Service cannot be created.
      at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
      at sun.reflect.NativeMethodAccessorImpl.invoke(
      at sun.reflect.DelegatingMethodAccessorImpl.invoke(
      at java.lang.reflect.Method.invoke(
      at com.tangoe.cmp.enterprise.ui.profile.EnterpriseSecurityHelper.getPreferences(
      at com.tangoe.cmp.common.ui.profile.Profile.getCurrentLocale(
      at org.quartz.simpl.SimpleThreadPool$
LVL 35

Expert Comment

ID: 17000368
Where is your class? do you have all relevant proxy/stub classes you need in the classpath?
Industry Leaders: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

LVL 35

Accepted Solution

girionis earned 500 total points
ID: 17000384
Also make sure you have *all* jars needed in the classpath.

Author Comment

ID: 17000959

It turned out it's a security/login issue (in lower level methods).....the userId wasn't available for the invoker of the method...thanks for your help!
LVL 35

Expert Comment

ID: 17000976
No problem. Please ask for a PAQ/Refund :)

Featured Post

Free Tool: SSL Checker

Scans your site and returns information about your SSL implementation and certificate. Helpful for debugging and validating your SSL configuration.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Introduction Java can be integrated with native programs using an interface called JNI(Java Native Interface). Native programs are programs which can directly run on the processor. JNI is simply a naming and calling convention so that the JVM (Java…
In this post we will learn how to make Android Gesture Tutorial and give different functionality whenever a user Touch or Scroll android screen.
Viewers learn about the scanner class in this video and are introduced to receiving user input for their programs. Additionally, objects, conditional statements, and loops are used to help reinforce the concepts. Introduce Scanner class: Importing…
Viewers will learn one way to get user input in Java. Introduce the Scanner object: Declare the variable that stores the user input: An example prompting the user for input: Methods you need to invoke in order to properly get  user input:

756 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question