Solved

Getting most common words from array

Posted on 2006-07-01
8
295 Views
Last Modified: 2012-06-21
I need a php script to find repeat words and output it.

Example text submitted from a textarea box:

drink energy
juice drink
hot cakes
fruit baskets
peanut butter and jelly
energy juice
fine wine
berry jelly

should return:

drink energy
juice drink
peanut butter and jelly
energy juice
berry jelly

because energy, juice, jelly and drink were most common, it should return those values from an array and also count it.


0
Comment
Question by:ray-solomon
  • 4
  • 4
8 Comments
 
LVL 29

Expert Comment

by:TeRReF
ID: 17025935
Something like this should work:
<?php

        $words = array('drink energy', 'juice drink', 'hot cakes', 'fruit baskets', 'peanut butter and jelly', 'energy juice', 'fine wine', 'berry jelly');
        $s = implode(' ', $words);
        $singlewords = array_unique(explode(' ', $s));
        //print_r($singlewords);
        //print($s);
        foreach($singlewords as $word) {
                preg_match_all('/'.$word.'/i', $s, $matches);
                $wordcount[$word] = count($matches[0]);
        }
        arsort($wordcount);
        $final_array = array();
        foreach($wordcount as $word=>$count) {
                foreach($words as $match) {
                        if (stripos($match, $word) !== false && !in_array($match, $final_array))
                                $final_array[] = $match;
                }
        }
        print_r($final_array);


?>
0
 
LVL 10

Author Comment

by:ray-solomon
ID: 17029212
Thanks TeRRef, but I get this error message:
Fatal error: Call to undefined function: stripos() in /home/...
0
 
LVL 29

Expert Comment

by:TeRReF
ID: 17029227
CHange this line:
                      if (stripos($match, $word) !== false && !in_array($match, $final_array))
to
                      if (strpos(strtolower($match), strtolower($word)) !== false && !in_array($match, $final_array))
0
Free Tool: Subnet Calculator

The subnet calculator helps you design networks by taking an IP address and network mask and returning information such as network, broadcast address, and host range.

One of a set of tools we're offering as a way of saying thank you for being a part of the community.

 
LVL 10

Author Comment

by:ray-solomon
ID: 17031869
Here is what the array contains:

Array ( [0] => drink energy [1] => juice drink [2] => peanut butter and jelly [3] => berry jelly [4] => energy juice [5] => fine wine [6] => fruit baskets [7] => hot cakes )


it should look like this:

Array ( [0] => drink energy [1] => juice drink [2] => peanut butter and jelly [3] => berry jelly [4] => energy juice )


because:
fine wine, fruit baskets and hot cakes do not contain any words that have been repeated two or more times in the array.

Hope that makes sense. BTW, thanks for helping me so far.
0
 
LVL 10

Author Comment

by:ray-solomon
ID: 17061204
Is there a way to make it output the most common words like I showed in my original question?
0
 
LVL 29

Accepted Solution

by:
TeRReF earned 500 total points
ID: 17061358
Sure. Sorry, I overlooked your last comment.
Here you go:

<?php

        $words = array('drink energy', 'juice drink', 'hot cakes', 'fruit baskets', 'peanut butter and jelly', 'energy juice', 'fine wine', 'berry jelly');
        $s = implode(' ', $words);
        $singlewords = array_unique(explode(' ', $s));
        //print_r($singlewords);
        //print($s);
        foreach ($singlewords as $word) {
                preg_match_all('/'.$word.'/i', $s, $matches);
                if (count($matches[0]) > 1)
                        $wordcount[$word] = count($matches[0]);
        }
        arsort($wordcount);
        $final_array = array();
        foreach ($wordcount as $word=>$count) {
                foreach ($words as $match) {
                        if (strpos(strtolower($match), strtolower($word)) !== false && !in_array($match, $final_array))
                                $final_array[] = $match;
                }
        }
        print_r($final_array);


?>

0
 
LVL 10

Author Comment

by:ray-solomon
ID: 17062135
Thank you! Awsome.
0
 
LVL 29

Expert Comment

by:TeRReF
ID: 17062314
You're welcome.
0

Featured Post

Free Tool: Site Down Detector

Helpful to verify reports of your own downtime, or to double check a downed website you are trying to access.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Popularity Can Be Measured Sometimes we deal with questions of popularity, and we need a way to collect opinions from our clients.  This article shows a simple teaching example of how we might elect a favorite color by letting our clients vote for …
Foreword (July, 2015) Since I first wrote this article, years ago, a great many more people have begun using the internet.  They are coming online from every part of the globe, learning, reading, shopping and spending money at an ever-increasing ra…
The viewer will learn how to dynamically set the form action using jQuery.
The viewer will learn how to create and use a small PHP class to apply a watermark to an image. This video shows the viewer the setup for the PHP watermark as well as important coding language. Continue to Part 2 to learn the core code used in creat…

790 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question