reading data from a text file in J2EE application

subirc,

> But then where do I specify the path on the server where the file will
> be uploaded? What will my upload form submit to?

You specify it in your source code, in the object where you actually do the upload. Here is some sample code: http://www.servlets.com/jservlet2/examples/ch04/UploadTest.java using the O'Reilly package.

If you go with CommonsMultipartResolver have a look here: http://www.up.ac.za/services/it/intranet/sysops/docs/spring/SpringReference.htm#mvc-multipart for information on how you can do it (source code, HTML code and any XML specific code).

> <form name="UploadForm onSubmit="??????"> . Can u pls show me (pseudocode)
> what will I have on the jsp and what will i have on the servlet? Just
> the relevant portion.....

In the HTML form you need to do something like this:

<form method="post" action="http://www.myserver.com/myservlet" enctype="multipart/form-data">
            <input type="file" name="myfilename"/>
            <input type="text" name="anothervariable"/>
            <input type="submit"/>
        </form>

For uploading the file(s) you need the following bit of code (from O'Reilly)

while (files.hasMoreElements()) {
        String name = (String)files.nextElement();
        String filename = multi.getFilesystemName(name);
        String original = multi.getOriginalFileName(name);
        String type = multi.getContentType(name);
        File f = multi.getFile(name);
        out.println();
      }

and to save a file on the disk you can do:

 MultipartRequest multi =
        new MultipartRequest(req, "/tmp", 50 *1024 * 1024,
          new com.oreilly.servlet.multipart.DefaultFileRenamePolicy());

You only have to change the "/tmp" folder to the one you want to save the files to.