find USERID error in JSP

hi experts,

I have jsp which call itself and check certain condition and displays record. If I search by userid, it shows me correct record
<%
if (request.getParameter.equals("Y"))
{
  String getUserId = request.getParameter("userid");
...
..
sb.append(" AND UPPER(USERID) LIKE UPPER('"+getUserId+any+"')");
...
..
rs= stmt.executeQuery(sb.toString());
..
while (rs.next())
 {
...
 }
}
%>

worked fine. Now I added condition if no userid exist display msg. "No users to display". If I type wrong ID it does display msg. But when I type correct ID I'm not getting the record display nor do I'm getting error. Seems like logic error after adding that if (!rs.next())

<%
if (request.getParameter.equals("Y"))
{
  String getUserId = request.getParameter("userid");
...
..
sb.append(" AND UPPER(USERID) LIKE UPPER('"+getUserId+any+"')");
...
..
rs= stmt.executeQuery(sb.toString());
..
if(!rs.next())
        {
          out.print("No users to display");                
        }  
while (rs.next())
 {
...
 }
}
%>


Thx.
PH
princehyderabadAsked:
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Peter KwanAnalyst ProgrammerCommented:
Does the SQL return only one row? If yes, then will not go into the while loop, since for each call of rs.next(), the cursor of the resultset will advance to next record, and if there is no more record, it will return false.

One way is to do this:

boolean hasUser = false;

while (rs.next()) {
     // do whatever
     hasUser = true;
}

if (!hasUser)
   out.print("No users to display");
0

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princehyderabadAuthor Commented:
It returns ONE row if userID matchs exactly the same. But if I search for userID 'a'  all userID starting with 'a' will be displayed. If I search "XYZ" then only one row is return where userId=XYZ
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