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Regeular expression to split a string

Posted on 2006-07-06
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Last Modified: 2010-03-31
I have a string in this format:
KEYWORD [int][int][name&surname&int&cell_number][String]

I want to strip out the keyword (leaving me with: '[int][int][name&surname&int&cell_number][String]' ) and then split the rest up into:
int
int
name&surname&int&cell_number
String

I thought something like:
String[] msg = message.replaceFirst("CT_FEEDBACK ", "").split( "\\[.*?\\]" );  
would work, but it doesn't...

Any ideas?
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Question by:riaancornelius
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27 Comments
 
LVL 86

Expert Comment

by:CEHJ
ID: 17049832
split( "\\[|\\]" );  
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Author Comment

by:riaancornelius
ID: 17049845
OK, why exactly? What is |
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Expert Comment

by:objects
ID: 17049848
try:

String[] tokens = substring(s.indexOf("[")).split("\\]{0,1}\\[");
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Expert Comment

by:objects
ID: 17049853
woops, should be:

String[] tokens = substring(s.indexOf("[")).split("\\]{0,1}\\[{0,1}");

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Expert Comment

by:CEHJ
ID: 17049863
>> OK, why exactly? What is |

Or
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Author Comment

by:riaancornelius
ID: 17049867
>> String[] tokens = substring(s.indexOf("[")).split("\\]{0,1}\\[{0,1}");
Explain that please?
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Expert Comment

by:objects
ID: 17049877
starting from first [
split on 0-1 ] followed by 0-1 [
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Author Comment

by:riaancornelius
ID: 17049880
I see CEHJ. Only problem is that it puts 4 blank elements as well.
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Expert Comment

by:girionis
ID: 17049901
       String s = "KEYWORD [int][int][name&surname&int&cell_number][String]";
        String[] msg = s.substring(s.indexOf("[")).split( "\\[|\\]" );
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Author Comment

by:riaancornelius
ID: 17049913
objects, that just splits it at every single character and puts a space everywhere there was a [ or ][
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Expert Comment

by:CEHJ
ID: 17049929
>>I see CEHJ. Only problem is that it puts 4 blank elements as well.

Yes. That's not easy to avoid. Just ignore elements in the array that are blank
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Author Comment

by:riaancornelius
ID: 17049930
girionis: Isn't that the same as CEHJ's first post?
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Expert Comment

by:girionis
ID: 17049937
> girionis: Isn't that the same as CEHJ's first post?

Not exactly, I am getting rid of the "KEYWORD " as well.
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Author Comment

by:riaancornelius
ID: 17049939
>> Yes. That's not easy to avoid. Just ignore elements in the array that are blank
Was just wondering whether there was an easy solution (in the regex) to do that.

Thanks CEHJ
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Accepted Solution

by:
objects earned 500 total points
ID: 17049942
it will too :)  try

        String[] msg = s.substring(s.indexOf("[")+1, s.length()-1).split( "\\]\\[" );
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Expert Comment

by:objects
ID: 17049949
> Was just wondering whether there was an easy solution (in the regex) to do that.

try my last post
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Author Comment

by:riaancornelius
ID: 17049957
>> Not exactly, I am getting rid of the "KEYWORD " as well.
My original solution does get rid of it as well.

As a matter of interest, Anybody know which is more efficient? substring() or replaceFirst().
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Expert Comment

by:objects
ID: 17049968
substring I'd reckon
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Expert Comment

by:girionis
ID: 17049972
> >> Not exactly, I am getting rid of the "KEYWORD " as well.
> My original solution does get rid of it as well.

Yes you are right, but my comment will replace *any* keyword, not just the "CT_FEEDBACK"
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Expert Comment

by:CEHJ
ID: 17049982
>> Was just wondering whether there was an easy solution (in the regex) to do that.

Can't think of one without substringing at the moment
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Author Comment

by:riaancornelius
ID: 17049984
good plan objects.

 String[] msg = s.substring(s.indexOf("[")+1, s.length()-1).split( "\\]\\[" );

This works perfectly.
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Expert Comment

by:objects
ID: 17049996
excellent :)
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Author Comment

by:riaancornelius
ID: 17050003
>> Yes you are right, but my comment will replace *any* keyword, not just the "CT_FEEDBACK"
This is true. I didn't pick that up, because in this class, keyword will always be "CT_FEEDBACK".

Interesting thought here though. If it's such a simple solution, it would actually be more efficient to use:
StringTokenizer st = new StringTokenizer( message.substring(message.indexOf("[")+1, message.length()-1), "][" );

Since stringTokenizer is a lot faster than String.split().
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Expert Comment

by:girionis
ID: 17050019
That would work too. As you see there are several solutions to a problem :)
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Author Comment

by:riaancornelius
ID: 17050039
I was just making it too complex...
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Expert Comment

by:CEHJ
ID: 17050221
>>Was just wondering whether there was an easy solution (in the regex) to do that.

You can do it like this actually:

String[] tokens = s.replaceFirst("KEYWORD\\s*\\[", "").split("\\[|\\]\\[|\\]");
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Expert Comment

by:CEHJ
ID: 17050237
This is more efficient:

String[] tokens = s.replaceFirst("KEYWORD\\s*\\[", "").split("\\]\\[|\\]");
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