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Stormchild69

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Using alternative to LIMIT command and using INNER JOIN in MS SQL Query

Hi,

I have the follwoing SQL:

SELECT     a.ContactID, a.CompanyID, a.ContactPrefix, a.ContactFName, a.ContactLName, a.ContactSurfix, a.ContactJobTitle, a.ContactPhone, a.ContactEmail,
                      b.CompanyName, b.CompanyPhone, b.CompanySegment, a.ContactMobile, a.ContactCustRelat, a.ContactAccntMng, a.ContactNotes,
                      b.CompanyFascimile, b.CompanyWeb, a.ContactRcdMng
FROM         Contact a INNER JOIN
                      Company b ON a.CompanyID = b.CompanyID
WHERE     (b.CompanySegment LIKE 'Finance') AND (a.ContactRemoved IS NULL) AND (b.CompanyRemoved IS NULL)
ORDER BY a.ContactID

This works fine but I also want to add a 'LIMIT' function.

I have the following code which performs the alternative to MySQL LIMIT command.

SELECT     contactid, contactlname
FROM         (SELECT     TOP 15 contactid, contactlname
                       FROM          (SELECT     TOP 45 contactid, contactlname
                                               FROM          contact
                                               ORDER BY contactid ASC) AS newtbl
                       ORDER BY contactid DESC) newtbl2
ORDER BY contactid

I need to use get the LIMIT capability of the second query into the first.

The reason for this is that I am using AJAX to call SQL lines on demand.

Any help would be really appreciated.

Thank you,

SC69

Avatar of dstanley9
dstanley9

How about this (not optimized):

SELECT     a.ContactID, a.CompanyID, a.ContactPrefix, a.ContactFName, a.ContactLName, a.ContactSurfix, a.ContactJobTitle, a.ContactPhone, a.ContactEmail,
                      b.CompanyName, b.CompanyPhone, b.CompanySegment, a.ContactMobile, a.ContactCustRelat, a.ContactAccntMng, a.ContactNotes,
                      b.CompanyFascimile, b.CompanyWeb, a.ContactRcdMng
FROM         Contact a INNER JOIN
                      Company b ON a.CompanyID = b.CompanyID
WHERE     (b.CompanySegment LIKE 'Finance') AND (a.ContactRemoved IS NULL) AND (b.CompanyRemoved IS NULL)
AND a.ContactID IN
 (SELECT     TOP 15 contactid
                       FROM          (SELECT     TOP 45 contactid
                                               FROM          contact
                                               ORDER BY contactid ASC)
                       ORDER BY contactid DESC)
ORDER BY a.ContactID
Avatar of Stormchild69

ASKER

Hello,

Many thanks but I got an error on line 11 (second ORDER from the bottom). I added bach 'AS newtbl' and it ran but produced a mess of duplicated contactids. Contactid is unique in that there should only be one per contact and I would hope that contactid 30-45 would be displayed. This is what I tried

SELECT     a.ContactID, a.CompanyID, a.ContactPrefix, a.ContactFName, a.ContactLName, a.ContactSurfix, a.ContactJobTitle, a.ContactPhone, a.ContactEmail,
                      b.CompanyName, b.CompanyPhone, b.CompanySegment, a.ContactMobile, a.ContactCustRelat, a.ContactAccntMng, a.ContactNotes,
                      b.CompanyFascimile, b.CompanyWeb, a.ContactRcdMng
FROM         Contact a INNER JOIN
                      Company b ON a.CompanyID = b.CompanyID
WHERE     (b.CompanySegment LIKE 'Finance') AND (a.ContactRemoved IS NULL) AND (b.CompanyRemoved IS NULL) AND (a.ContactID IN
                          (SELECT     TOP 15 a.contactid
                            FROM          (SELECT     TOP 45 a.contactid
                                                    FROM          contact a
                                                    ORDER BY a.contactid ASC) AS newtbl
                            ORDER BY a.contactid DESC))
ORDER BY a.ContactID


Many thanks for trying,

SC69
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Avatar of dstanley9
dstanley9

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Avatar of Anthony Perkins
Is this SQL Server 2005?
Hi,

I am running SQL Server 2000.

Thank you for your help.

I added 'AS newtbl' and then your solution worked as required,

Thanks,

SC69
While I appreciate the points, you appear to have awarded me in error.  See here:

I accepted the wrong answer. Now what?
https://www.experts-exchange.com/Databases/Microsoft_SQL_Server/help.jsp#hi17