SharonPeffer
asked on
area of a parcel of land that has four unequal sides
How would I caluclate the area of a parcel of land that has four unequal sides?
The four sides are: A.) 209.83ft. B.) 195.57ft. C.) 196.42ft. D.) 50.02ft.,
The angles are: AB=65 degrees, BC=73 degrees, CD=109 degrees, DA=109 degrees
The four sides are: A.) 209.83ft. B.) 195.57ft. C.) 196.42ft. D.) 50.02ft.,
The angles are: AB=65 degrees, BC=73 degrees, CD=109 degrees, DA=109 degrees
ASKER CERTIFIED SOLUTION
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
The simplest way is to divide the quadrilateral into two triangles, and compute their areas using the formula:
A = (side1 * side2 * sin(angle)) / 2
A = (side1 * side2 * sin(angle)) / 2
no help at all
B 195.57
diag 218.15 Diag 218.1530308
S1 311.78
A1 18595.83
C 196.42
D 50.02
diag 218.15
S2 232.30
A2 4635.22
A1+A21 23231.05 <== Square Feet