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area of a parcel of land that has four unequal sides

Posted on 2006-07-09
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How would I caluclate the area of a parcel of land that has four unequal sides?  
The four sides are: A.) 209.83ft.  B.) 195.57ft. C.) 196.42ft. D.) 50.02ft.,
The angles are:  AB=65 degrees, BC=73 degrees, CD=109 degrees, DA=109 degrees
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Question by:SharonPeffer
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d-glitch earned 375 total points
ID: 17068726
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by:d-glitch
ID: 17068754
A      209.83            AB=65 deg      
B      195.57                  
diag      218.15            Diag      218.1530308
                        
S1      311.78                  
A1      18595.83                  



C      196.42
D      50.02
diag      218.15

S2      232.30
A2      4635.22

A1+A21      23231.05  <==   Square Feet
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by:e_tadeu
ID: 17068784
The simplest way is to divide the quadrilateral into two triangles, and compute their areas using the formula:

A = (side1 * side2 * sin(angle)) / 2


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by:Northpark2297
ID: 21046038
no help at all
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