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asp.net c# 2.0 convert double to percent

Posted on 2006-07-10
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Last Modified: 2008-01-09
How do I convert a double value to percent for comparison?

Example of code with static entries commented:
Double C = Double.Parse(TextBox1.Text); //77500
Double R = Double.Parse(TextBox2.Text); //33600
Double I = Double.Parse(TextBox3.Text); //241500
Double TCA = C + R + I;

Double AP = Double.Parse(TextBox4.Text); //129000
Double NP = Double.Parse(TextBox6.Text); //8400
Double OCL = Double.Parse(TextBox7.Text); //117000
Double TCL = AP + NP + OCL;

Double CR;
 CR = TCA / TCL;
 Label9.Text = CR.ToString();
 if (CR < 2.0)
  Label18.Text = "CR is under";
 else
  Label18.Text = "CR is above";


End Results:

Name      value                  compareto
CR            1.98484848484848          2.0%
0
Comment
Question by:fwsteal
5 Comments
 
LVL 9

Expert Comment

by:daniel_balla
ID: 17076121
Hi fwsteal,
You want to compare it to percent of what?

Cheers!
0
 

Author Comment

by:fwsteal
ID: 17077498
format the display of the CR to display as a % such as:
   1.98%
and still be able to compare it:
if (1.98 < 2.0)

so my report description can read as: 1.98% is less than 2.0%, so don't buy.
0
 
LVL 9

Accepted Solution

by:
bele04 earned 250 total points
ID: 17078478
Since you're just going to display it why don't you just append it to the the string like:

Response.Output.Write("{0:#.##}% is less than 2.0%, so don't buy", CR);

or if you're going to display it to a label:

label1.Text = CR.ToString("{#.##}") + "% is less than 2.0%, so don't buy.";
0
 

Author Comment

by:fwsteal
ID: 17080995
CR.ToString("#.##") = .62

I'm not sure how to display it as 62.0?

How should the following be written? CR.ToString("#.##") + "%";
0
 
LVL 8

Assisted Solution

by:kaliyugkaarjun
kaliyugkaarjun earned 250 total points
ID: 17081501
0

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