c# 2.0 convert double to percent

How do I convert a double value to percent for comparison?

Example of code with static entries commented:
Double C = Double.Parse(TextBox1.Text); //77500
Double R = Double.Parse(TextBox2.Text); //33600
Double I = Double.Parse(TextBox3.Text); //241500
Double TCA = C + R + I;

Double AP = Double.Parse(TextBox4.Text); //129000
Double NP = Double.Parse(TextBox6.Text); //8400
Double OCL = Double.Parse(TextBox7.Text); //117000
Double TCL = AP + NP + OCL;

Double CR;
 CR = TCA / TCL;
 Label9.Text = CR.ToString();
 if (CR < 2.0)
  Label18.Text = "CR is under";
  Label18.Text = "CR is above";

End Results:

Name      value                  compareto
CR            1.98484848484848          2.0%
Who is Participating?
bele04Connect With a Mentor Commented:
Since you're just going to display it why don't you just append it to the the string like:

Response.Output.Write("{0:#.##}% is less than 2.0%, so don't buy", CR);

or if you're going to display it to a label:

label1.Text = CR.ToString("{#.##}") + "% is less than 2.0%, so don't buy.";
Hi fwsteal,
You want to compare it to percent of what?

fwstealAuthor Commented:
format the display of the CR to display as a % such as:
and still be able to compare it:
if (1.98 < 2.0)

so my report description can read as: 1.98% is less than 2.0%, so don't buy.
fwstealAuthor Commented:
CR.ToString("#.##") = .62

I'm not sure how to display it as 62.0?

How should the following be written? CR.ToString("#.##") + "%";
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