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Only a doubt about creating component in run time

My doubt is that I am creating two components with the same name but in different procedures, can I have a problem with this?


See this code



Procedure OpenDB;

  procedure DeleteTMPDB(code: Integer);
  Var
    TQ : Tadoquery;
  Begin
    TQ : Tadoquery.Create(nil);
    ... etc
    Try
     Finally
      FreeAndNil(TQ)
    End
  End

Var
  TQ : Tadoquery;
Begin

  Begin
    TQ : Tadoquery.Create(nil);
    ... etc
    Try
       With TQ do
       Begin
          Sql.Add('Select * from table');
          Open;
       End;
       While TQ.Not Eof do
       Begin
          DeleteTMPDB(TQ.FieldByName('ID').AsInteger);
          TQ.Next;
       End
     Finally
      FreeAndNil(TQ)
    End
  End

End
0
hidrau
Asked:
hidrau
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1 Solution
 
Russell LibbySoftware Engineer, Advisory Commented:

The variables are scoped differently, so there isn't an issue.

Russell

0
 
Russell LibbySoftware Engineer, Advisory Commented:
Eg, an example to test scope of variables:

procedure TestScope;

  procedure TestInnerScope;
  var S:      String;
  begin
     ShowMessage(S);
  end;

var S:        String;
begin

  S:='Hello world';
  TestInnerScope;

end;
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hidrauAuthor Commented:
so, I could tell that they are connected by procedure, is it?
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Russell LibbySoftware Engineer, Advisory Commented:
For further info, the Delphi help on the topic "Scope" reads as follows:

Naming conflicts

When one block encloses another, the former is called the outer block and the latter the inner block. If an identifier declared in an outer block is redeclared in an inner block, the inner declaration overrides the outer one and determines the meaning of the identifier for the duration of the inner block. For example, if you declare a variable called MaxValue in the interface section of a unit, and then declare another variable with the same name in a function declaration within that unit, any unqualified occurrences of MaxValue in the function block are governed by the second, local declaration. Similarly, a function declared within another function creates a new, inner scope in which identifiers used by the outer function can be redeclared locally.
0
 
Russell LibbySoftware Engineer, Advisory Commented:
>> so, I could tell that they are connected by procedure, is it?

Not sure I follow what you are asking... The only connection is in the fact that the DeleteTMPDB can only be called from within OpenDB, as DeleteTMPDB is a nested block. But the variable TQ  (because of the inner scope redeclaration) is 2 individual variables, where the usage depends on the scope (block level being executed)

Russell
0
 
hidrauAuthor Commented:
Yeah, TQ are two different variables and none of them affects each other. That's all that I would like to know. :)
0

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