asked on

How remove decimal and 2 trailing zeros from multiple values in field

Hello,

I have a table that has numeric values (eg. 2506.00) that I have already convert to text. Now I need to remove the decimal and the 2 trailing zeros. The field name is Group_Index. Also, in case you need to know, the values are not all 4 digits. They actually start at 1.00, then go all the way to 2506.00.

So I want 2506.00 to be changed to 2506.

Would I do this using an update query? How should it be written? If you can provide me with the SQL that would be even better!

Thanks!

rockiroads

u could try round

round(2506.00,0)

rockiroads

or format

format(2506.00,"0")

GRayL

update mytable set myfld = replace(myfld,".00","");

rockiroads

yes, update query, thats what u asked for in your last sentence!
Well I guess GRayL has given u the syntax
and after re-reading, values are not all digits

stick with his solution

pelampe

ASKER

Couldn't get it to work.

Here is the SQL:

UPDATE Parcel_Info SET Parcel_Info.Group_Index = replace(Group_Index,".00","");

Here is the error message: Undefined function 'replace' in expression

Let me know what I'm doing wrong, please.

BTW, using Access 97 is that is relevant.

Phil.

Carl2002

If its text you could use instr() to locate the decimal point then take everything to the left of it.

heres the syntax

Expr1: IIf(InStr([field1],".")=0,[field1],Left([field1],InStr([field1],".")))

Just an idea.

Carl.

pelampe

ASKER

Carl,

Almost worked. Took the 2 trailing zeros off. But left the decimal.

So it went from this: 2506.00

to this 2506.

Any ideas?

ASKER CERTIFIED SOLUTION

Jim P.

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SOLUTION

GRayL

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rockiroads

Ray, here is a version of Replace for A97

Public Function A97Replace(pstrIn, pstrOld, pstrNew)

Dim strWork As String
Dim strL As String
Dim strR As String
Dim intX As Integer
strWork = pstrIn

Do
intX = Nz((InStr(1, strWork, pstrOld, vbTextCompare)), 0)
If intX > 0 Then
strL = Left$(strWork, intX - 1)
strR = Right$(strWork, (Len(strWork) - intX - Len(pstrOld) + 1))
strWork = strL & pstrNew & strR
Else
Exit Do 'Escape from the loop if nothing else to do
End If
Loop

A97Replace = strWork
End Function

so u could still use your original solution

update mytable set myfld = a97replace(myfld,".00","");

UPDATE Parcel_Info SET Parcel_Info.Group_Index = A97Replace(Group_Index,".00","");

But Jim's and your alternative solution will work just as well so as long as it just ends with .00

rockiroads

By the way, the post if for information only, not an attempt to get points! so please do not accept my post as part of any solution

Jim P.

No objecions

pelampe

ASKER

Hello All,

I apologize for not responding sooner, but I just got back from a two week vacation, yesterday.

BTW, you all have been a TREMENDOUS help to me in getting a better grip on how to use Access and I GREATLY apprieciate having a forum like this!

Please accept my humble apology.

Have a great day!

Phil