Solved

# E

Posted on 2006-07-14
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Hi,

Why are the following conditions correct? Could someone please explain to me.

1. 16 % 3 < 22 ==  6 / 3 >= 2

2. 9 > = 7 + 3 && 7 % 3 == 1

3. 6 > 2 || 25 / 5 == 4

4. 7 <= 9 || 6 > 5 && 7 == 2

5. 25 > 3 && !(6==4)
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Question by:dandeliondream
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Accepted Solution

Infinity08 earned 125 total points
ID: 17107945
I suggest you add brackets using the operator precedence table :

http://www.difranco.net/cop2220/op-prec.htm

so you get a clearer view on what goes with what.

Then just calculate step by step.

I'll give you one example for the first question - the rest I leave up to you :

16 % 3 < 22 ==  6 / 3 >= 2

is the same as :

(((16 % 3) < 22) ==  ((6 / 3) >= 2))

So :

((1 < 22) ==  (2 >= 2))

Or :

(1 ==  1)

Or :

1

which is TRUE.
0

LVL 53

Assisted Solution

Infinity08 earned 125 total points
ID: 17107957
Note that this step :

(1 ==  1)

is very dangerous in actual code, because there's no guarantee that both sides will be 1 (the only guarantee is that they will be values different from 0).

So, on some platforms, this might be :

(1 == 2)

which would be FALSE.

For these exercises you can assume that TRUE is always 1 though !
0

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Author Comment

ID: 17108121
Thanks Infinity08.
0

LVL 53

Expert Comment

ID: 17108161
If you have trouble figuring out the other 4, feel free to post your solutions here, and I'll take a look at them.
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