• C

called object is not a function

Hi I am getting error in the following line....

int m=0;
for(l=0; txt[l] != '\0'; l++)
  {
      if((txt[l] != ' ') && (txt[l] != '\r')  (txt[l] != '\n'))
      {
            str[m]=txt[l];
          m++;
      }
  }
  str[l]='\0';

txt is of type const char *txt
char str[1000];

error message "called object is not a function "


sudarshantkAsked:
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DineshJolaniaConnect With a Mentor Commented:
Compiler assumes that following syntax is a function
(txt[l] != '\r')  (txt[l] != '\n')   and hence the error.
0
 
dennis_georgeCommented:
The following statement in your program is ill-formed....
if((txt[l] != ' ') && (txt[l] != '\r')  (txt[l] != '\n'))

each condition should be separated by a conditional statement....
e.g.
if( (txt[l] != ' ') && ((txt[l] != '\r') || (txt[l] != '\n'))  )

0
 
cwwkieCommented:
should probably be and instead of or:

if( (txt[l] != ' ') && ((txt[l] != '\r') && (txt[l] != '\n'))  )

otherwise the whole statement would not make much sense.
0
 
sudarshantkAuthor Commented:
Thanks
0
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