how to watch process (exe) is running under window and restart it if it 'die'?

Posted on 2006-07-17
Medium Priority
Last Modified: 2008-02-01
I have a few critical process (exe) programs are running in the background server processes, that are started by scheduler task.   I can see it thru 'taskmgr'.

Now I need to do more:  if any one of the critical processor is 'die', - ie. not in the taskmgr anymore.  How can I re-start it without human attend (or course, it will be nice to be able to send me an email, then start it, and if continue start x times, it will not try to start again).    

1.  Someone told me there is a window utility can do this?  if so, I do not know where to find.  and how to use it
2. if there is NO such utility, anyone know how to write it, or if there is someone sell it.  let me know.

Need experts give me some advise and information on this subject.


Question by:mshox1
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LVL 86

Expert Comment

by:Mike Tomlinson
ID: 17122965
You could try something like the script I posted here:
LVL 26

Expert Comment

ID: 17124413
if you use xp or higher and your critical tasks are written in service, then use windows OS recovery that available on service

Author Comment

ID: 17124522
EDDYKT,  we do use XP or higher to write the program in VB6.  what are you means by written in service?  what is wondows OS recovery that available on services..   can you provide me some direction on getting this info,  especially with examples.


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LVL 26

Expert Comment

ID: 17124687
>>what are you means by written in service?


There is recovery tab on each service and you can configure to restart your service if it fail
LVL 26

Expert Comment

ID: 17124689
>>There is recovery tab on each service

There is recovery tab on each service properties

Accepted Solution

justchat_1 earned 1500 total points
ID: 17127334
This will tell you if a program is running:

You can check it using a timer (ex:every minute) and use shell to reload it if it crashed

Note: If the program hangs but is still running vb makes it very hard to find out-this will require some serious windows hooks...

Expert Comment

ID: 17291724
I think I answered the question correctly-awaiting an author response

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