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Posted on 2006-07-18
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Last Modified: 2009-07-29
Hello AJAX Expert,

I am trying to implement the Select/Dropdown AJAX tag from the following link.  The Select/Dropdown tag work the following way: when selection within a dropdown field, a second select field will be populated.

See the following link: http://ajaxtags.no-ip.info/

The demo has 2 files associated with it, a JSP and a JAVA servlet.  The servlet name is DropdownServlet.  How is this servlet called from the JSP with the following ajax:select tag?

<ajax:select
  baseUrl="${contextPath}/dropdown.view"
  source="make"
  target="model"
  parameters="make={make}"
  preFunction="initProgress"
  postFunction="resetProgress"
  errorFunction="reportError"
  parser="new ResponseXmlParser()" />

I am using Netbeans IDE with JSP named dropdown and servlet named DropdownServlet.   I think DropdownServlet is supposed to return model given make to the JSP to be displayed in the chained dropdown box.

Heres a code snippet from the demo JSP:

<form action="." class="basicForm">
  <fieldset>
    <legend>Choose Your Car</legend>
    <label for="make">Make:</label>
    <select id="make">
      <option value="">Select make</option>
      <option value="Ford">Ford</option>
      <option value="Honda">Honda</option>
      <option value="Mazda">Mazda</option>
    </select>
    <span id="progressMsg" style="display:none;"><img alt="Indicator" src="./styles/indicator.gif" /> Loading...</span>

    <label for="model">Model:</label>
    <select id="model" disabled="disabled">
      <option value="">Select model</option>
    </select>
  </fieldset>
</form>
<div id="errorMsg" style="display:none;border:1px solid #e00;background-color:#fee;padding:2px;margin-top:8px;width:300px;font:normal 12px Arial;color:#900"></div>

<script type="text/javascript">
 /*
  * USER DEFINED FUNCTIONS
  */

function initProgress() {
  Element.show('progressMsg');
}

function resetProgress() {
  // show marker emblem
  var index = $('make').selectedIndex;
  var automaker = $('make').options[index].text;
  var imgTag = $('makerEmblem');
  if (index > 0) {
    imgTag.src = "./styles/" + automaker.toLowerCase() + "_logo.gif";
  }

  Effect.Fade('progressMsg');
}

function reportError() {
  if ($('model').options.length == 0) {
    $('errorMsg').innerHTML = "Dropdown busted!";
  }
  Element.show('errorMsg');
  setTimeout("Effect.DropOut('errorMsg')", 2500);
}
</script>

<ajax:select
  baseUrl="${pageContext.request.contextPath}/DropdownServlet"
  source="make"
  target="model"
  parameters="make={make}"
  preFunction="initProgress"
  postFunction="resetProgress"
  errorFunction="reportError"
  parser="new ResponseXmlParser()" />

Can you tell be how the servlet gets called in this AJAX demo?

Getting desperate.  Appreciate the help!!
0
Comment
Question by:i808237
1 Comment
 
LVL 3

Accepted Solution

by:
anumalas earned 1000 total points
ID: 17182642
Hi

by default ajax:select will call cjajax.js java script. all the servlet communication functionality is written in that java script to communicate with the java sources like servlet or action classes

i suggest you to go thru that java script file

please refer the link, download cjajax.js and go thru

http://www.servletsuite.com/servlets/ajaxseltag.htm

Hope this will solve your confusion :)
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