Find non-alphabetic char in string in VB

The simplest solution is to use a regular expression. I presume this is enforcing some password complexity rules, so you can do something like:

       Dim Str As String = "AD1@aYaZ6"
        Dim re As New System.Text.RegularExpressions.Regex("^[A-Za-z]*$", System.Text.RegularExpressions.RegexOptions.IgnoreCase)
        Dim m As System.Text.RegularExpressions.Match = re.Match(Str)
        If m.Success Then
            MsgBox("String must have 1 non-alphabetic character")
            Return False
        End If
        Return True

Thanks murray,
I know to do it in .NET way, but unfortunately iam using VB 3. So any user procedure / function etc.

hint: We got LIKE keyword similar to regEx, but i dont know to use it.

any suggestions.....

I forgot - if the string can be any length, you have to really check character by character (I haven't checked this, so there may be a typo):

      For iX=0 To Str.length
           If Str.Char[iX] like "[!A-Za-z]" then
               return True
           End If
       Next
       Return False

Just do:

str = "AD1@aYaZ"
Dim i As Integer, token As Integer
For i = 1 To Len(str)
   token = Asc(Mid$(str, i, 1))
   If token < 65 Or (token > 90 And token < 97) Or token > 122 Then Return True
Next i
MsgBox "String must have 1 non-alphabetic character"
Return False

Oh, you have to substitute the stupid return mechanism for "Return."  I forgot.  So it'd be fooFighterFnc = True: Exit Function, etc.