Remove decimal places in text box value

Dear All ,

Please help me for this simple question .

I have text box value like given below .

Text1.text = 12.75

From this value I want to get whole number only .

Ex. text2.text = 12


Thanks

PChandima.


PChandimaAsked:
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Ryan ChongBusiness Systems Analyst , ex-Senior Application EngineerCommented:
try:

text2.text = format(text1.text, "0")
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Ryan ChongBusiness Systems Analyst , ex-Senior Application EngineerCommented:
May try this instead:

text2.text = fix(text1.text)
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Ryan ChongBusiness Systems Analyst , ex-Senior Application EngineerCommented:
a better handling.. just in case the value of text1 is non-numeric:

if isnumeric(text1.text) then
  text2.text = fix(text1.text)
else
   text2.text = "0" 'or default value
end if
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PChandimaAuthor Commented:
Dear Ryancys

Thanks For your comments

PChandima
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alainbrydenCommented:
Lol you guys are rediculous! It's so much simpler than that.

Dim number As Integer
number = Int(Text1.text)   'Visual basic automatically TRUNCATES when creating integers

'''Assume Text1.text = 12.99999
'''Then number = 12
'''Careful, because if Text1.text = -45.01827
'''Then number = -46
'''(negative numbers round down)


alain
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alainbrydenCommented:
[If you're going straight back to a string then: Text2.text = Int( text1.text ) ]
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Ryan ChongBusiness Systems Analyst , ex-Senior Application EngineerCommented:
Int, Fix Functions
http://msdn2.microsoft.com/en-us/library/t4dseb50.aspx

>>number = Int(Text1.text)
yes, this will work IF and ONLY when Text1.text is a numeric value, else a Type Mismatch error will appear.

>>Lol you guys are rediculous!
Frankly, we are just volunteer to help here, however i don't expect to get that as a response here!
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alainbrydenCommented:
If isNumeric(Text1.text) then number = Int(Text1.text)

Didn't mean to offend you. I suppose that was innapropriate and appologize, I was simply explaining that there were more simple means.

Alain
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Ryan ChongBusiness Systems Analyst , ex-Senior Application EngineerCommented:
no worries ; )
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Ryan_RIT Systems AdministratorCommented:
easiest way would be to use the Left() function

ie txt1.text = Left(txt1.Text, InStr(txt1.Text, "."))
if necessary use the CStr() function to convert to string but i don't think you'll need to
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smokey965Commented:
An easier way would be
text1.text = "123.456"

text1.text = text1.text + 0

That will make text1.text = "123"

This works on my computer.
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Ryan_RIT Systems AdministratorCommented:
did you try it with "123.999"?
it appears that he always wants to round the number down
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alainbrydenCommented:
smokey's solution is effectively using the Int ( ) function, because it typecasts text1.text as an integer to match the type of "0" which is integer.

Ryan's solution has the same effect as the Fix() function, although it is not nearly as fast. String functions take much much longer to execute then a simple truncation function. A one time use case doesn't matter though. Only if this were code used alot in a loop or recursive call.

Alain
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Ryan_RIT Systems AdministratorCommented:
is there a vb function like the one in excel called ROUNDDOWN() ?
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smokey965Commented:
Here's another one 'text1.text = split(text1.text, ".")(0)'
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