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Remove decimal places in text box value

Posted on 2006-07-20
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Last Modified: 2012-01-05
Dear All ,

Please help me for this simple question .

I have text box value like given below .

Text1.text = 12.75

From this value I want to get whole number only .

Ex. text2.text = 12


Thanks

PChandima.


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Question by:PChandima
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17 Comments
 
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Expert Comment

by:Ryan Chong
ID: 17144785
try:

text2.text = format(text1.text, "0")
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Accepted Solution

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Ryan Chong earned 50 total points
ID: 17144793
May try this instead:

text2.text = fix(text1.text)
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Expert Comment

by:Ryan Chong
ID: 17144799
a better handling.. just in case the value of text1 is non-numeric:

if isnumeric(text1.text) then
  text2.text = fix(text1.text)
else
   text2.text = "0" 'or default value
end if
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Author Comment

by:PChandima
ID: 17144857
Dear Ryancys

Thanks For your comments

PChandima
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Expert Comment

by:alainbryden
ID: 17145932
Lol you guys are rediculous! It's so much simpler than that.

Dim number As Integer
number = Int(Text1.text)   'Visual basic automatically TRUNCATES when creating integers

'''Assume Text1.text = 12.99999
'''Then number = 12
'''Careful, because if Text1.text = -45.01827
'''Then number = -46
'''(negative numbers round down)


alain
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Expert Comment

by:alainbryden
ID: 17146034
[If you're going straight back to a string then: Text2.text = Int( text1.text ) ]
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Expert Comment

by:Ryan Chong
ID: 17147061
Int, Fix Functions
http://msdn2.microsoft.com/en-us/library/t4dseb50.aspx

>>number = Int(Text1.text)
yes, this will work IF and ONLY when Text1.text is a numeric value, else a Type Mismatch error will appear.

>>Lol you guys are rediculous!
Frankly, we are just volunteer to help here, however i don't expect to get that as a response here!
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Expert Comment

by:alainbryden
ID: 17148202
If isNumeric(Text1.text) then number = Int(Text1.text)

Didn't mean to offend you. I suppose that was innapropriate and appologize, I was simply explaining that there were more simple means.

Alain
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Expert Comment

by:Ryan Chong
ID: 17148235
no worries ; )
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Expert Comment

by:Ryan_R
ID: 17151678
easiest way would be to use the Left() function

ie txt1.text = Left(txt1.Text, InStr(txt1.Text, "."))
if necessary use the CStr() function to convert to string but i don't think you'll need to
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Expert Comment

by:smokey965
ID: 17164023
An easier way would be
text1.text = "123.456"

text1.text = text1.text + 0

That will make text1.text = "123"

This works on my computer.
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Expert Comment

by:Ryan_R
ID: 17164480
did you try it with "123.999"?
it appears that he always wants to round the number down
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Expert Comment

by:alainbryden
ID: 17164705
smokey's solution is effectively using the Int ( ) function, because it typecasts text1.text as an integer to match the type of "0" which is integer.

Ryan's solution has the same effect as the Fix() function, although it is not nearly as fast. String functions take much much longer to execute then a simple truncation function. A one time use case doesn't matter though. Only if this were code used alot in a loop or recursive call.

Alain
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Expert Comment

by:Ryan_R
ID: 17172071
is there a vb function like the one in excel called ROUNDDOWN() ?
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Expert Comment

by:smokey965
ID: 17172111
Here's another one 'text1.text = split(text1.text, ".")(0)'
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