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unique 48 bits number to unique 32 bits number

Hi,
as stated in the header, does anyone know an algorithm or something like that which enables me to use a 48 bit unique number and store it as a unique 32 bit number??
Regards
0
TError104
Asked:
TError104
4 Solutions
 
sunnycoderCommented:
Hi TError104,

It is not possible to store 2^48 unique numbers are 2^32 unique numbers ... there are bound to be collisions and there will be several 48 bit numbers which will map to common 32 bit numbers .... this is unavoidable ....

Cheers!
sunnycoder
0
 
rajeev_devinCommented:
If you want to store a 48 bit number then use two data members instead

32 bit integer
16 bit short integer

which is 48 bit in size.
0
 
nafis_devlprCommented:
you can use the segment:offset method, like save the first 16bit in a 16bit short int as the segment and the next 32bit in a 32bit int as the offset, by this i mean the bit mask of the 48bit in a 16+32 bit split

you can try union

union INT
      {
            unsigned short int first16;
            unsigned int next32;
      };
or a struct or union of 6 char data

union INT
      {
            unsigned char s[6];
      };

Nafis
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AxterCommented:
Why not use a 64 bit integer to store the 48bit number?

__int64 My48_bitNum;
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itsmeandnobodyelseCommented:
Do you know the whole set of 48-bit numbers where the uniqueness needs to keep guaranteed ? If yes, you might take the index of each number as a unique 32 bit equivalence (I assume the size of the set is less than 4 billions).

If no, you could simply count the 4bit numbers you have to convert and and return the count value as a unique id:

typedef unsigned short UI48[3];

unsigned int I48ToI32(UI48 ui48)
{
     static unsigned int count = 0;
     return ++count;
}

In case you could get the same input twice  you would need to store all numbers converted to a dictionary and check for existence before incrementing count.

struct UI48
{
    unsigned short us3[3];
    bool operator<(const UI48& u) const { return us3[0] < u.us3[0] ||
                                                ( us3[0] == u.us3[0] && us3[1] < u.us3[1]) ||
                                                ( us3[0] == u.us3[0] && us3[1] == u.us3[1]  && us3[2] < u.us3[2]);
                                                         }
    bool operator==(const UI48& u) const { return ( us3[0] == u.us3[0] && us3[1] == u.us3[1] && us3[2] == u.us3[2]); }
};

unsigned int I48ToI32(UI48 ui48)
{
     static unsigned int count = 0;
     static std::map<UI48, unsigned int> uimap;
     if (uimap.find(ui48) == uimap.end())
           uimap[ui48] = ++count;
     return  uimap[ui48];
}

Regards, Alex
0
 
Infinity08Commented:
First of all : what do you want to achieve ?

1) lossless compression : impossible as stated by sunnycoder (unless there are max. 2^32 valid values possible for the 48bit integer)

2) conversion of a 48bit value to a 32bit value : only possible if the maximum value of the 48bit integer is 2^32-1

3) something else : please specify
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