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How do I make sure a file is a CSV file before i start to try and process it?

Posted on 2006-07-20
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Last Modified: 2006-11-18
Hi,

I have a webapp, and we require people to upload a CSV file for various activities - data eventually gets stored in a DB however.
It all works if you upload a CSV file...
but if I upload file in a different format.. how can I detect this before/during/after processing the file into arrays etc?

Thanks in advance :)
Rob
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Question by:skaap2k
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6 Comments
 
LVL 7

Expert Comment

by:maUru
ID: 17148676
depends on how thorough you want to be,

you can try something like:

$delimiter = ',';
$fields = 4; // if this is 0 it will try and 'figure out' the number of fields

$file = file('blabla.csv');
foreach ($file as $key => $line) {
  $numfields = 0;
  $numfields = substr_count($line, $delimiter) + 1;

  if ($key == 0 && $fields > 0) {
        $fields = $numfields;
      }
   }
  if ($numfields != $fields) {
      die('too many fields on line ' . $key ');
  }
}

could be fixed up a bit, but basically it will die if there is an irregularity in the file.
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LVL 7

Expert Comment

by:maUru
ID: 17148696
of course this is very very simple, there is no checking for quoted fields, delimeters nested between quotes on fields etc.
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Author Comment

by:skaap2k
ID: 17148737
I tried uploading a MS Word doc earlier, and it had decided that there were 2 fields, and 82 rows ...so I dont think that'd work very well, is there perhaps a way I could eliminate other files by working out what they are first - the CSV files i'll be getting dont have a fixed amount of fields or rows..
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LVL 7

Expert Comment

by:maUru
ID: 17148773
they dont have a fixed amount of fields? thats not right.

and here is a cleaned up version of what i wrote:

<?

$file = file('test.csv');
$fields = 3; // if this is 0 it will try and 'figure out' the number of fields
if (checkCSV('test.csv', 3)) {
      echo 'file good';
}

function checkCSV($file, $fields=0, $delimiter=',') {
      $delimiter = ',';

      foreach ($file as $key => $line) {
            $numfields = 0;
            $numfields = substr_count($line, $delimiter) + 1;

            if ($key == 0 && $fields == 0) {
                  $fields = $numfields;
            }
            if ($numfields != $fields) {
                  echo 'irregular on line ' . $key;
                  return false;
            }
      }
      return true;
}
?>
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LVL 7

Accepted Solution

by:
maUru earned 2000 total points
ID: 17148793
sorry that was wrong:

<?

$file = 'test.csv';
$fields = 3; // if this is 0 it will try and 'figure out' the number of fields
if (checkCSV($file, 3)) {
      echo 'file good';
}

function checkCSV($filepath, $fields=0, $delimiter=',') {
      $file = file($filepath);

      foreach ($file as $key => $line) {
            $numfields = 0;
            $numfields = substr_count($line, $delimiter) + 1;

            if ($key == 0 && $fields == 0) {
                  $fields = $numfields;
            }
            if ($numfields != $fields) {
                  echo 'irregular on line ' . $key;
                  return false;
            }
      }
      return true;
}
?>
0
 

Expert Comment

by:madman2
ID: 17199097
if($_FILES['bestand']['type'] == "application/vnd.ms-excel" && eregi('\.csv$', $_FILES['bestand']['name'])
  {
  FILE OK
  }

application/vnd.ms-excel == mime type of the uploaded document
first test all possible mime types by using
print $_FILES['bestand']['type'];

Then of course you have to check the content of that file
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