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how many different numbers can six bits represent?

Posted on 2006-07-20
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Last Modified: 2012-06-21
Does any body know how many different numbers can six bits represent?
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Question by:amoe
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Assisted Solution

by:Raynard7
Raynard7 earned 50 total points
ID: 17151116
64 (including 0)

2^6
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by:amoe
ID: 17151402
how do i convert 7Bh to decimal?
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Expert Comment

by:Davidshc76
ID: 17151416
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LVL 14

Expert Comment

by:CyrexCore2k
ID: 17151488
Programatically?

Function HexToInt(sStr)
Dim iInt, temp, x
iInt = 0
For x = 1 To Len(sStr)
    temp = Val(Mid(sStr, x, 1))
    If temp = 0 And Mid(sStr, x, 1) <> "0" Then
        If UCase(Mid(sStr, x, 1)) = "A" Then
            temp = 10
        ElseIf UCase(Mid(sStr, x, 1)) = "B" Then
            temp = 11
        ElseIf UCase(Mid(sStr, x, 1)) = "C" Then
            temp = 12
        ElseIf UCase(Mid(sStr, x, 1)) = "D" Then
            temp = 13
        ElseIf UCase(Mid(sStr, x, 1)) = "E" Then
            temp = 14
        ElseIf UCase(Mid(sStr, x, 1)) = "F" Then
            temp = 15
        End If
    End If
    temp = temp * (16 ^ (Len(sStr) - x))
    iInt = iInt + temp
Next
HexToInt = iInt
End Function
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Accepted Solution

by:
v_karthik earned 50 total points
ID: 17151490
>>how do i convert 7Bh to decimal?

you mean manually? Just write down the bits representing 7 and B side by side like this

0111 1011

(note: 7 is 0111, B is 1011 or 11 in decimal)

Now read the binary in decimal (hope u know that), it becomes 123.
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LVL 15

Expert Comment

by:Ryan_R
ID: 17151542
1 bit (as a 1 or a 0)
8 bits (1 byte) = 1 character
therefore 6 bits isn't enough to represnt any characters - you need multiples of 8
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Expert Comment

by:InteractiveMind
ID: 17153097
> therefore 6 bits isn't enough to represnt any characters

For standard character encodings, you are correct.
But if he's implementing his own format, then there's no problem (so long as he can represent those 6 bits).
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Expert Comment

by:Ryan_R
ID: 17153407
fair enough, is there any really good reason why this is needed (whats wrong with standard chars?)
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Expert Comment

by:InteractiveMind
ID: 17153744
Well, if there's only a limited number of characters that need representing, then by using 6 bits instead of 8, you will be of course saving 2 bits per character.

When memory is a *major* issue, and you need to represent a very large number of characters, then this small sacrifice is somewhat significant.

But it's unlikely that you will ever be in that situation nowadays; so really, no.. I personally cannot think of any good reason why you wouldn't just stick with the standard character encodings (or at least use an 8-bit byte, which the low-level architecture directly supports; rather than trying to implement your own format).
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Expert Comment

by:Ryan_R
ID: 17162225
thanks - i was thinking on similar lines as you
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