Solved

how to check if a String has one word or two words

Posted on 2006-07-21
7
237 Views
Last Modified: 2010-03-31
Hi

I have a string which have state name
like
Arizona
californinia
South carolina
North carolina

what I need is to check

if(state is one word{

get standard abbreviation

}
else
{

get first letter of both the words

}

Would anyone know how to do this

Any help will be greatly appreciated
0
Comment
Question by:huzefaq
7 Comments
 
LVL 86

Accepted Solution

by:
CEHJ earned 500 total points
ID: 17154583
You could keep a Map of states, then

                  Pattern p = Pattern.compile("^(.).+\\b(.).+");
                  Matcher m = p.matcher(inputString);
                  if (m.matches()) {
                        String letterOne = m.group(1);
                        String letterTwo = m.group(2);
                        System.out.printf("%s %s\n", letterOne, letterTwo);
                  }
                  else {
                        String state = stateMap.get(inputString);
                  }
0
 
LVL 23

Expert Comment

by:Ajay-Singh
ID: 17155064
you can try this too,

if(state.indexOf(' ') > 0) {
// The state has more than 1 words.
}
else {
}

This works efficiently if the state has words seperated by one/more spaces
0
 

Author Comment

by:huzefaq
ID: 17155108
CEHJ Thanks

But

 System.out.printf("%s %s\n", letterOne, letterTwo);

this line is giving error

0
Is Your Active Directory as Secure as You Think?

More than 75% of all records are compromised because of the loss or theft of a privileged credential. Experts have been exploring Active Directory infrastructure to identify key threats and establish best practices for keeping data safe. Attend this month’s webinar to learn more.

 

Author Comment

by:huzefaq
ID: 17155125
Ajay-Singh

How can I get the first leter of both the words then
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 17155210
>>System.out.printf("%s %s\n", letterOne, letterTwo);

You can delete that
0
 
LVL 2

Expert Comment

by:RoyalNepal
ID: 17155511
You can do like this...too.



if (state.equals (""))//if state string is empty dont do anything
      return;

state = state.trim(); //takes out the spaces from first or last index

if(state.indexOf(' ') != -1)
{
  //return abbrev..it has only one word
}
else
{
//it has two words....so to take out the first letter..
//eg...if it has "South carolina" it returns South
  int index = state.indexOf(' ');
  return state.substring(0,index+1);
}

0
 
LVL 86

Expert Comment

by:CEHJ
ID: 17156150
:-)
0

Featured Post

Is Your Active Directory as Secure as You Think?

More than 75% of all records are compromised because of the loss or theft of a privileged credential. Experts have been exploring Active Directory infrastructure to identify key threats and establish best practices for keeping data safe. Attend this month’s webinar to learn more.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

An old method to applying the Singleton pattern in your Java code is to check if a static instance, defined in the same class that needs to be instantiated once and only once, is null and then create a new instance; otherwise, the pre-existing insta…
Introduction This article is the first of three articles that explain why and how the Experts Exchange QA Team does test automation for our web site. This article explains our test automation goals. Then rationale is given for the tools we use to a…
Viewers will learn about basic arrays, how to declare them, and how to use them. Introduction and definition: Declare an array and cover the syntax of declaring them: Initialize every index in the created array: Example/Features of a basic arr…
Viewers will learn about the regular for loop in Java and how to use it. Definition: Break the for loop down into 3 parts: Syntax when using for loops: Example using a for loop:

867 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

16 Experts available now in Live!

Get 1:1 Help Now